如何将值从视图传递到iOS中的另一个视图?

时间:2015-07-31 03:48:08

标签: ios json swift

    import UIKit

    class TableController: UITableViewController {

    var items = NSMutableArray()
    var TableData:Array< String > = Array < String >()
    var json:String = ""

    var quantity2: Int = 0
    var shortDate: String = ""

    @IBOutlet var myTableView: UITableView!
    var arrayOfMenu: [Nutrisi] = [Nutrisi]()

    override func viewDidLoad() {
        super.viewDidLoad()
        self.setUpMenu()
        self.myTableView.delegate = self
        self.myTableView.dataSource = self
    }

    override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return arrayOfMenu.count
    }

    override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {

        let cell: CustomCell = tableView.dequeueReusableCellWithIdentifier("cell") as! CustomCell
        let menu = arrayOfMenu[indexPath.row]
        cell.setCell(menu.type, rightlabeltext: menu.unit, imagename: menu.image)
        var data = Nutritiondata(type: menu.type, amount: String(cell.value).toInt()!)
        var json = JSONSerializer.toJson(data)
        self.json = json
        return cell
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
    }

    func do_table_refresh()
    {
        dispatch_async(dispatch_get_main_queue(), {
            self.tableView.reloadData()
            return
        })
    }

    func setUpMenu()
    {

        var json: JSON = JSON (data: NSData())
        let frame:CGRect = CGRect(x: 110, y: 300, width: view.frame.width, height: 700)
        self.tableView.frame = frame
        DataManager.getnutritionsDataFromFileWithSuccess{ (data) -> Void in
            json = JSON(data: data)
            let results = json["results"]
            for (index: String, subJson: JSON) in results {
            }
            for (var i = 0; i < json["nutritions"].count; i++) {
                if let type = json["nutritions"][i]["type"].string {
                    if let icon: AnyObject = json["nutritions"][i]["icon"].string {
                        self.items.addObject(icon)
                        if let unit = json["nutritions"][i]["unit"].string {

                            dispatch_async(dispatch_get_main_queue(), {self.tableView!.reloadData()})
var menu = Nutrisi(type: type, unit: unit, image: icon as! String)
                                    self.arrayOfMenu.append(menu)
                                    self.TableData.append(type + unit )
                                    self.do_table_refresh();               
                        }
                    }
                }
            }
        }
    }
}

我已经使用了这段代码,并且在表控制器视图上运行良好,但我想创建一个新的视图控制器,打印jsonjson在表控制器上运行良好,并打印出来)

所以,我创建了一个新的视图控制器连接到另一个名为senddata的类,我应该用什么命令在那里打印json,我想打印那个json数据时按下按钮:

import UIKit

class SendData: UIViewController{

    @IBAction func tes(sender: AnyObject) {
        println()
    }

    override func viewDidLoad() {
        super.viewDidLoad()
    }    
}

1 个答案:

答案 0 :(得分:1)

你可以把JSON数据放在一个全局结构中,所以最终会看起来像这样。

TableViewController.swift

struct JSON {
  static var JSONData = ""
}

  class TableController: UITableViewController {

    var items = NSMutableArray()
    var TableData:Array< String > = Array < String >()
    var json:String = ""

    var quantity2: Int = 0
    var shortDate: String = ""

    @IBOutlet var myTableView: UITableView!
    var arrayOfMenu: [Nutrisi] = [Nutrisi]()

    override func viewDidLoad() {
        super.viewDidLoad()
        self.setUpMenu()
        self.myTableView.delegate = self
        self.myTableView.dataSource = self
    }

    override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return arrayOfMenu.count
    }

    override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {



        let cell: CustomCell = tableView.dequeueReusableCellWithIdentifier("cell") as! CustomCell
        let menu = arrayOfMenu[indexPath.row]
        cell.setCell(menu.type, rightlabeltext: menu.unit, imagename: menu.image)
        var data = Nutritiondata(type: menu.type, amount: String(cell.value).toInt()!)
        var json = JSONSerializer.toJson(data)
        JSON.JSONData = json
        return cell
    }

SendData.swift

class SendData: UIViewController{

    @IBAction func tes(sender: AnyObject) {
        println(JSON.JSONData)
    }

    override func viewDidLoad() {
        super.viewDidLoad()

    }

}