我正在学习d3,我使用“dataset”变量作为图形的值, 我希望使用dataset.nombre值标记d3图形,但我只能使用dataset.numbers,这是一个简化的代码版本:
<body>
<div id="container2"></div>
<script>
var dataset = {
numbers: [15, 3, 10, 2, 14,17,1],
nombre:["a","b","c","d","e","f","g"]
};
var color = d3.scale.category20();
var pie = d3.layout.pie()
.sort(null);
var piedata = pie(dataset.apples);
var arc = d3.svg.arc()
.innerRadius(radius - 100)
.outerRadius(radius - 50);
var svg = d3.select("#container2").append("svg")
.attr("width", width)
.attr("height", height)
.append("g")
.attr("transform", "translate(" + width / 2 + "," + height / 2 + ")");
var path = svg.selectAll("path")
.data(piedata)
.enter().append("path")
.attr("fill", function(d, i) { return color(i); })
.attr("d", arc);
svg.selectAll("text").data(piedata)
.enter()
.append("text")
.attr("text-anchor", "middle")
.attr("x", function(d) {
var a = d.startAngle + (d.endAngle - d.startAngle)/2 - Math.PI/2;
d.cx = Math.cos(a) * (radius - 75);
return d.x = Math.cos(a) * (radius - 20);
})
.attr("y", function(d) {
var a = d.startAngle + (d.endAngle - d.startAngle)/2 - Math.PI/2;
d.cy = Math.sin(a) * (radius - 75);
return d.y = Math.sin(a) * (radius - 20);
})
.text(function(d) { return d.value; })
.each(function(d) {
var bbox = this.getBBox();
d.sx = d.x - bbox.width/2 - 2;
d.ox = d.x + bbox.width/2 + 2;
d.sy = d.oy = d.y + 5;
});
svg.append("defs").append("marker")
.attr("id", "circ")
.attr("markerWidth", 6)
.attr("markerHeight", 6)
.attr("refX", 3)
.attr("refY", 3)
.append("circle")
.attr("cx", 3)
.attr("cy", 3)
.attr("r", 3);
svg.selectAll("path.pointer").data(piedata).enter()
.append("path")
.attr("class", "pointer")
.style("fill", "none")
.style("stroke", "black")
.attr("marker-end", "url(#circ)")
.attr("d", function(d) {
if(d.cx > d.ox) {
return "M" + d.sx + "," + d.sy + "L" + d.ox + "," + d.oy + " " + d.cx + "," + d.cy;
} else {
return "M" + d.ox + "," + d.oy + "L" + d.sx + "," + d.sy + " " + d.cx + "," + d.cy;
}
});
</script>
</body>
答案 0 :(得分:1)
理想情况下,您将对象而不是数字作为传递给饼图布局的数据;那么你就可以直接使用这些数据了。在您的情况下,您仍然可以使用索引:
.text(function(d, i) { return dataset.nombre[i]; })
完整演示here。