在下图中,我根据数据需要转置的前三列获得当前数据和预期数据
表格查询:
drop table ##Test
CREATE TABLE ##Test
(paymentid varchar(30),
claimid bigint,
Lineno1 int,
groupcode varchar(2),
Carc int,
adjustmentamt float,
RARC varchar(30),
Edit1 varchar(30),
Remit varchar(30),
)
INSERT INTO ##Test
(paymentid ,
claimid ,
Lineno1 ,
groupcode ,
Carc ,
adjustmentamt ,
RARC ,
Edit1 ,
Remit )
VALUES
('QP18502291',14205893514,2,'CO',84,75.55,'N20','','D18')
('QP15930339',14127612308,1,'OA',23,263,'','ClaimDetail.COBAmt','') ,
('QP15930339',14127612308,1,'OA',23,21.69,'','ClaimDetail.COBAmt',''),
('QP18502291',14205893514,2,'OA',23,78.77,'','ClaimDetail.COBAmt',''),
('QP18502291',14205893514,2,'OA',97,66.55,'N20','','D18')
select * from ##Test
答案 0 :(得分:0)
可能重复post并查看解决方案。
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT ',' + QUOTENAME(col+cast(rn as varchar(10)))
from
(
select row_number() over(partition by paymentid order by Lineno1) rn
from ##Test
) d
cross apply
(
select 'groupcode', 1 union all
select 'carc', 2 union all
select 'adjustmentamt', 3 UNION ALL
SELECT 'rarc',4 UNION ALL
SELECT 'Edit1' ,5 UNION ALL
SELECT 'remit',6
) c (col, so)
group by col, rn, so
order by rn, so
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT paymentid, claimid,Lineno1,' + @cols + '
from
(
select paymentid, claimid,Lineno1, col+cast(rn as varchar(10)) col, value
from
(
select paymentid, claimid,Lineno1, groupcode, carc, adjustmentamt,rarc,Edit1,remit,
row_number() over(partition by paymentid order by Lineno1) rn
from ##Test
) t
cross apply
(
select ''groupcode'', groupcode union all
select ''carc'', cast(carc as varchar(50)) union all
select ''adjustmentamt'', cast(adjustmentamt as varchar(50)) union all
select ''rarc'', rarc union all
select ''Edit1'' , Edit1 union all
select ''remit'' , remit
) c (col, value)
) x pivot
(
max(value)
for col in (' + @cols + ')
) p '
execute(@query)