绑定两个JSpinners递增和递减

时间:2015-07-30 19:50:58

标签: java swing jspinner

我创建了两个带有netbeans Form的JSpinner,我想链接两个JSpinner,这样如果其中一个的值减少,则其他增量的值减去,反之亦然。我尝试使用这段代码,但它不起作用:

 int currentValue = durexep_spin.getValue();
private void durexep_spinPropertyChange(java.beans.PropertyChangeEvent evt) {                                            


  int p = soldexep_spin.getValue();
  int q = durexep_spin.getValue();
  if(q<currentValue){
    soldexep_spin.setValue(p+1);  
  }
  else if (q>currentValue){
      soldexep_spin.setValue(p-1);
  }

1 个答案:

答案 0 :(得分:1)

您可以在其构造函数中创建一个javax.swing.event.ChangeListener的子类,其中包含两个引用:JSPinner base和JSpinner image。然后编码stateChanged方法以从基数的当前值更新图像的值(假设您知道两个值的总和是什么)。

最后,您只需实例化侦听器的两个实例,并将一个实例附加到每个JSpinner。

{
    // ... Initialization of the JPanel ...
    int constantSum=10;
    soldexep_spin.addChangeListener(new MyListener(soldexep_spin, durexep_spin, constantSum));
    durexep_spin.addChangeListener(new MyListener(durexep_spin, soldexep_spin, constantSum));
}

private class MyListener implements javax.swing.event.ChangeListener
{
    private final JSpinner base;

    private final JSpinner image;

    private final int constantSum;

    public MyListener(JSpinner base, JSpinner image, int constantSum)
    {
        super();
        this.base=base;
        this.image=image;
        this.constantSum=constantSum;
        // Initializes the image value in a coherent state:
        updateImage();
    }

    public void stateChanged(ChangeEvent e)
    {
        updateImage();
    }

    private void updateImage()
    {
        int baseValue=((Number)this.base.getValue()).intValue();
        int imageValue=((Number)this.image.getValue()).intValue();
        int newImageValue=this.constantSum - baseValue;
        if (imageValue != newImageValue)
        {
            // Avoid an infinite loop of changes if the image value was already correct.
            this.image.setValue(newImageValue);
        }
    }