Question

在我的代码的评论部分，我试图通过合计$ totalmin和$ totalhours来获得总工作时间，但是我得到了错误。我得到了：

Warning: mysqli_query() expects parameter 1 to be mysqli, object given in C:\xampp\htdocs\app\login\gr\ewh.php on line 66  ($result = mysqli_query($conn,$sql);)

Warning: mysqli_error() expects parameter 1 to be mysqli, object given in C:\xampp\htdocs\app\login\gr\ewh.php on line 68 (printf("Error: %s\n", mysqli_error($conn));)

我做错了什么？是语法吗？数据库连接或其他东西..

  try {
        $conn = new PDO('mysql:host=localhost;dbname=jj', 'root', 'awd');
        $conn->exec("set names utf8");
        $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
        $num_rows = $conn->query('SELECT COUNT(*) FROM employees')->fetchColumn(); 


        $stmt = $conn->prepare("SELECT employees.name,employees.division FROM employees WHERE employees.status='Employed' A LIMIT :start,:end");
        $stmt->bindParam(':start', $pages->limit_start, PDO::PARAM_INT);
        $stmt->bindParam(':end', $pages->limit_end, PDO::PARAM_INT);
        $stmt->execute();
        $result = $stmt->fetchAll();

        $ewhtable = "<table class='sortable'><th>Employee Name</th></tr>\n";
        foreach($result as $row) {
            $years=explode("/", $row[2]);
            $years[2]=intval(date ('Y')) - $years[2];

/*       
 $sql="SELECT WorkingHours FROM WOrkHours WHERE AFNumber=$row[0]";
        $result = mysqli_query($conn,$sql);
        if (!$result) {
            printf("Error: %s\n", mysqli_error($conn));
            exit();
        }
        while($row = mysqli_fetch_array($result)){
                $temp = explode(":", $row['WorkingHours']);
                $hoursworked+=intval($temp[0]);
                $minsworked+=intval($temp[1]);
                $totalworkedhours=$hoursworked+($minsworked/60);
                $totalmin= $totalworkedhours % 60;
                $totalhours=$totalworkedhours-$totalmin;
        }
            */

Answer 1

您似乎正在从PDO切换到MySQLi .. ..stick到PDO，您的问题将不存在。

$conn是您的PDO数据库句柄，随后将无法传递给mysqli_ *函数。

显示sql php函数时出错

1 个答案: