请原谅格式 - 它一直给我"你的代码没有格式化#34;这个问题的错误。我有一个代码,包含一个打印图像的画布。然后我跟踪用户的鼠标坐标,如果它们与文本文件中找到的坐标匹配,我想提示用户。这是一个Web应用程序,用于补充C ++ OpenCV程序,该程序可检测blob及其存在的坐标。文本文件采用以下格式:label x y
。
001 101 305
是blob 001中坐标(101,305)的行.PHP正在读取每一行并在空格处爆炸。
文本文件如下所示:
001 101 303
001 101 304
001 101 305
001 101 306
001 101 307
001 101 308
001 101 309
001 101 310
001 102 301
001 102 302
<script> // functions to make canvas and place PNG overlay image
<?php
$XYFile = fopen("cpp/textdump/coordinates/imagetesting.txt.txt","r") or die ("file reading error");
$coordinates = array(); // create coordinates array
while (!feof($XYFile)) { // while not at last line of file
$uncatXY = fgets($XYFile); // read one line of file
$splitXY = explode(" ", $uncatXY); // create new array element when a space is present
$label = $splitXY[0]; // declare blob label
$x = $splitXY[1]; // declare x
$y = $splitXY[2]; // declare y
array_push($coordinates, $label, $x, $y);
} // push into coordinates array
fclose($XYFile); // close file
?>
var js_array = <?php echo(json_encode($coordinates)); ?> // convert PHP array to javascript object notation format
// requires PHP 5.2 or higher, which I believe to be on the server. It's certainly on my localhost server.
console.log(js_array); // dev
$(document).ready(function() {
window.onload = function() {
var c = document.getElementById("solarCanvas");
var ctx = c.getContext("2d");
ctx.fillStyle = "#00FFFF"; // cyan fill
var img = document.getElementById("testimage");
img.src = 'cpp/images/PNG/imagetesting.png'; //"cpp/images/" + date + ".png";
ctx.drawImage(img, 0, 0);
c.addEventListener('click', function() { }, false);
// functions for color & coordinates on mouse movement/clicl
$('#solarCanvas').mousemove(function(e) {
var c = document.getElementById("solarCanvas");
var ctx = c.getContext("2d"); // temp declaration bug fix -- can't find root cause, so redec
var pos = findPos(this);
var x = e.pageX - pos.x;
var y = e.pageY - pos.y;
var coord = "x=" + x + ", y=" +y;
var p = ctx.getImageData(x, y, 1, 1).data;
var hex = ("#" + 000000 + rgbToHex(p[0], p[1], p[2]).slice(-6));
$('#status').html(coord + "<br>" + hex);
console.log(x + "," + y + "---" + coord + " at " + hex);
});
$('#solarCanvas').click(function(e) {
var c = document.getElementById("solarCanvas");
var ctx = c.getContext("2d");
var pos = findPos(this);
var xNum = e.pageX - pos.x;
var yNum = e.pageY - pos.y;
var xStr = xNum.toString();
var yStr = yNum.toString();
for(var i = 0; i < js_array.length; i++) {
if(js_array[i] === xStr) {
return i;
console.log(i);
if(i > -1) {
alert("yahoo!");
}
}
}
console.log(js_array);
console.log(xStr);
console.log(yStr);
});
}
});
// old architecutre
// mixed array_search ( mixed $needle, array $haystack [, bool $strict = false ] );
// searches haystack for needle
// pseudocode
//if ((e.pageX - pos.x) exists in col 2 && (e.pageY-pos.y) is in same row in col 3) {
</script>
我已经浏览了此代码的许多版本,并发布了我现在所拥有的内容。我目前正在严格使用X坐标。一旦它工作,我将添加Y. [...] 我已经考虑过这个事实,即PHP爆炸&amp; json_encode正在保存字符串,所以我做了一个.toString()函数,但这似乎没有任何帮助。例如,我的控制台日志就像x / y / pos of x in array / pos of y in array
101
305
-1
-1
答案 0 :(得分:0)
这里略微改写了您的代码。
我做了什么:
PHP代码:
funTaylor m x
JS:
<?php
$file = file("cpp/textdump/coordinates/imagetesting.txt.txt"");
$coordinates = array();
for ($line in $file) {
array_push($coordinates, explode(" ", $line);
}
?>
var coords = <?= json_encode($coordinates) ?>;