Question

晚上好！
我服务方面的问题很小。起初，我有几个TextViews的片段。在这些TextView中，我想从我的服务中添加文本。这个简单的服务代码

public class ChallengeService extends Service {
    final String LOG_TAG = "myLogs";
    private String url = "";
    public static ArrayList<Exercises> exercises = new ArrayList<>();

    public void onCreate() {
        super.onCreate();
        Log.d(LOG_TAG, "onCreate");
    }

    public int onStartCommand(Intent intent, int flags, int startId) {
        Log.d(LOG_TAG, "onStartCommand");
        url = intent.getStringExtra("Challenge_URL");
        new getChallenge(url).execute();
        return super.onStartCommand(intent, flags, startId);
    }

    public void onDestroy() {
        super.onDestroy();
        Log.d(LOG_TAG, "onDestroy");
    }

    public IBinder onBind(Intent intent) {
        Log.d(LOG_TAG, "onBind");
        return null;
    }

    public class getChallenge extends AsyncTask<Void,Void,String> {

        String mUrl;
        OkHttpClient client = new OkHttpClient();
        String result = "";

        public getChallenge(String url) {
            this.mUrl = url;
        }

        HttpURLConnection urlConnection = null;
        BufferedReader reader = null;

        @Override
        protected String doInBackground(Void... params) {
            Log.d("Background", "inBackground");
            try {
                URL mUrl = new URL(url);
                Log.d("URL!!!!", "url = " + url);
                urlConnection = (HttpURLConnection) mUrl.openConnection();
                urlConnection.setRequestMethod("GET");
                urlConnection.connect();
                InputStream inputStream = urlConnection.getInputStream();
                StringBuffer buffer = new StringBuffer();
                reader = new BufferedReader(new InputStreamReader(inputStream));
                String line;
                while ((line = reader.readLine()) != null) {
                    buffer.append(line);
                }
                result = buffer.toString();

            } catch (Exception e) {
                e.printStackTrace();
            }
            return result;
        }

        @Override
        protected void onPostExecute(String strJson) {
            super.onPostExecute(strJson);
            Log.d(LOG_TAG, strJson + " " + url);
            exercises = ParseJSON.ChallengeParseJSON(strJson);
            Log.d("Challenges", "challenges: " + exercises.get(0).getName() + " " + exercises.get(1).getName());
        }
    }
}

我需要将练习的发送清单发送到我的片段，我该如何制作？我是服务新手，我没有任何想法，请帮助我

Answer 1

只需从您的服务广播结果，然后通过广播接收器

将其接收到您的片段中

例如，您可以在onPostExecute这样的

中播放您的练习

    @Override
    protected void onPostExecute(String strJson) {
        super.onPostExecute(strJson);
        Log.d(LOG_TAG, strJson + " " + url);
        exercises = ParseJSON.ChallengeParseJSON(strJson);
        Log.d("Challenges", "challenges: " + exercises.get(0).getName() + " " + exercises.get(1).getName());

        Intent intent = new Intent(FILTER); //FILTER is a string to identify this intent
        intent.putExtra(MY_KEY, exercises); 
        sendBroadcast(intent);
    }

但是，您的练习对象需要parcelable才能顺利运行。或者您可以只播放原始的json字符串并在片段中调用ParseJSON.ChallengeParseJSON(strJson);

然后在你的片段中创建一个接收器

private BroadcastReceiver receiver = new BroadcastReceiver() {

@Override
public void onReceive(Context context, Intent intent) {
  ArrayList<Exercises> exercises = intent.getExtras().get(MY_KEY);

  //or
  //exercises = ParseJSON.ChallengeParseJSON(intent.getStringExtra(MY_KEY));

   }
};

在您的onResume

中

和register

  @Override
 protected void onResume() {
   super.onResume();
   getActivity().registerReceiver(receiver, new IntentFilter(FILTER));
 }

您还需要使用getActivity().unregisterReceiver(receiver);

在onPause中取消注册

如果感兴趣，您还可以阅读更多相关信息here

Answer 2

你可以通过2种方法来实现。

将数据保存到数据库并以片段形式获取数据。
使用广播

将数据从Service发送到Fragment，Android

2 个答案: