Question

好的，我有一张包含以下信息的表

Company, Employee, Work Date, Job Number
ABC      1234      06/01/15    5555
ABC      1234      06/02/15    5555
ABC      1234      06/03/15    5555
ABC      1234      06/04/15    5555
ABC      1234      06/05/15    5555
ABC      1234      06/06/15    5555
ABC      1234      06/11/15    6666
ABC      1234      06/12/15    6666
ABC      1234      06/13/15    6666
ABC      1234      06/14/15    6666
ABC      1234      06/15/15    6666
ABC      1234      06/16/15    6666

我想要的记录是

ABC      1234      06/11/15    6666

我的第一步是使用此查询获取最近的工作日期

SELECT TCH.Company_Code, TCH.Employee_Code, CAST(TCH.Work_Date AS DATE) AS Work_Date, DENSE_RANK() OVER (PARTITION BY TCH.Employee_Code ORDER BY CAST(TCH.Work_Date AS DATE) DESC) AS DateRank
    FROM PR_TIME_CARD_HISTORY_MC TCH WITH (NOLOCK)
    WHERE TCH.Company_Code <> 'XYZ' 
    AND LTRIM(RTRIM(TCH.Employee_Code)) = '22164'

第二步是将它连接回原始表以获得作业，但我似乎无法获得作业的记录集来获得最小日期。

SELECT TCH.Company_Code, TCH.Employee_Code, TCH.Job_Number, CAST(TCH.Work_Date AS DATE) AS Work_Date, DENSE_RANK() OVER (PARTITION BY TCH.Job_Number ORDER BY CAST(TCH.Work_Date AS DATE) ASC) AS JobRank
    FROM PR_TIME_CARD_HISTORY_MC TCH WITH (NOLOCK)
    WHERE TCH.Company_Code <> 'XYZ' 
    AND TCH.Pay_Type = 'R'
    AND LTRIM(RTRIM(TCH.Employee_Code)) = '22164'

希望这有所帮助，肯定可以使用一些指导。

Answer 1

我认为以下查询应该完成这项工作：

SELECT company, employee, work_date,job_number FROM
(
SELECT 
 TCH.Company_Code as company, 
 TCH.Employee_Code as employee,
 TCH.Job_Number as job_number, 
 CAST(TCH.Work_Date AS DATE) AS Work_Date, 
 ROW_NUMBER() OVER (PARTITION BY TCH.Employee_Code,TCH.Company_Code ORDER BY TCH.Job_Number DESC,CAST(TCH.Work_Date AS DATE) ASC) AS DateRank
    FROM PR_TIME_CARD_HISTORY_MC TCH WITH (NOLOCK) 
) q
WHERE q.DateRank=1

Answer 2

编辑：

要获得最高Job_Number的最低日期，您需要同时应用ORDER BY：

SELECT *
FROM
 (
    SELECT TCH.Company_Code, TCH.Employee_Code, TCH.Job_Number,
       CAST(TCH.Work_Date AS DATE) AS Work_Date, 
       ROW_NUMBER() -- latest row gets 1
       OVER (PARTITION BY TCH.Employee_Code 
             ORDER BY TCH.Job_Number DESC, CAST(TCH.Work_Date AS DATE)) AS DateRank
    FROM PR_TIME_CARD_HISTORY_MC TCH WITH (NOLOCK)
    WHERE TCH.Company_Code <> 'XYZ' 
    AND LTRIM(RTRIM(TCH.Employee_Code)) = '1234'
 ) AS dt
WHERE DateRank = 1

但如果工作数量没有增加，你需要一个不同的逻辑：

SELECT *
FROM
 (
    SELECT TCH.Company_Code, TCH.Employee_Code, TCH.Job_Number,
       CAST(TCH.Work_Date AS DATE) AS Work_Date, 
       ROW_NUMBER() -- latest row gets 1
       OVER (PARTITION BY TCH.Employee_Code 
             ORDER BY CAST(TCH.Work_Date AS DATE)) AS DateRank, 

         -- The start date of each job
       MIN(CAST(TCH.Work_Date AS DATE))
       OVER (PARTITION BY TCH.Employee_Code, TCH.Job_Number) AS FirstWorkDate
    FROM PR_TIME_CARD_HISTORY_MC TCH WITH (NOLOCK)
    WHERE TCH.Company_Code <> 'XYZ' 
    AND LTRIM(RTRIM(TCH.Employee_Code)) = '1234'
 ) AS dt
WHERE DateRank = 1

Answer 3

使用where子句中的嵌套查询尝试此操作：

SQL Fiddle

MS SQL Server 2008架构设置：

messages = ["\n".join(m.decode() for m in mssg[1]) for mssg in messages]

查询1 ：

CREATE TABLE TimeCard
(
  Company VARCHAR(10),
  Employee INT,
  WorkDate Date,
  JobNumber Int
)

INSERT INTO TimeCard
VALUES
  ('ABC', 1234, '06/01/15', 5555),
  ('ABC', 1234, '06/02/15', 5555),
  ('ABC', 1234, '06/03/15', 5555),
  ('ABC', 1234, '06/04/15', 5555),
  ('ABC', 1234, '06/05/15', 5555),
  ('ABC', 1234, '06/06/15', 5555),
  ('ABC', 1234, '06/11/15', 6666),
  ('ABC', 1234, '06/12/15', 6666),
  ('ABC', 1234, '06/13/15', 6666),
  ('ABC', 1234, '06/14/15', 6666),
  ('ABC', 1234, '06/15/15', 6666),
  ('ABC', 1234, '06/16/15', 6666)

<强> Results ：

SELECT TC.Company, TC.Employee, MIN(TC.WorkDate) AS WorkDate, TC.JobNumber
FROM TimeCard TC
WHERE   TC.Company <> 'XYZ' AND
        TC.Employee = 1234 AND
        TC.JobNumber =
        (    
            -- Get Max JobNumber for the Max Workdate 
            SELECT MAX(JobNumber) 
            FROM TimeCard TC3
            WHERE TC3.WorkDate = 
                -- Get Max WorkDate of Employee
                (
                    SELECT MAX(WorkDate) 
                    FROM TimeCard TC2 
                    WHERE TC2.Employee = TC.Employee
                )
            GROUP BY TC3.Employee
        )
GROUP BY TC.Company, TC.Employee, TC.JobNumber

试图让最小日期超出设定范围

3 个答案: