Question

我遇到了将带有连字符/破折号的电子邮件插入mysql的问题。使用的框架是 CodeIgniter 。该项目托管在 GoDaddy （如果这有帮助）。有效的电子邮件是：

name@domain.com，name @ test.domain.com，first.last @ domain.com，   first.last@test.domain.com,name.123@domain.com,first_last@domain.com,first_last@test.domain.com

不起作用的电子邮件是，但它们在localhost中正常工作：


first-last@domain.com,first-last@test.domain.com

以下是插入电子邮件的表单：

<form method="post" action="<?php echo base_url('index.php?/codes');?>"> <div class="form-group"> <label>Email</label> <input type="text" name="email" id="email" placeholder="Email" class="form-control"> </div> <div class="form-group"> <label>Waiver Code</label> <input type="text" name="code" id="code" placeholder="Code" class="form-control"> </div> <button class="btn btn-sm btn-success" onclick="autogen()" name="saveCode">Generate</button> </form>

从'javascript'调用的autogen()函数：

function autogen() { var randomstring = Math.random().toString(36).slice(-6); var date = new Date().getFullYear(); randomstring = date+randomstring; randomstring = randomstring.toUpperCase(); var email = $('#email').val(); var code = $('#code'); if (!email) { alert("Email is required!"); $('#email').focus(); } else { code.val(randomstring); alert("Email: "+email+"\nCode: "+randomstring); $.ajax({ url: "<?php echo base_url('index.php?/genCode/"+email+"/"+randomstring+"');?>", data: ({'email': email, 'code': randomstring}), type: "post", success: function(response, textStatus, jqXHR){ location.reload(); alert('Code added'); }, error: function(jqXHR, textStatus, errorThrown){ console.log("The following error occured: "+ textStatus, errorThrown); } }); } }

最后来自CodeIgniter的插入脚本

class GenCode extends CI_Controller { public function index($email="", $code="") { //$data = array('email' => $this->db->escape($email), 'code' => $code, 'user' => $this->session->userdata('username')); //$query = $this->db->insert('codes', $data); $query = $this->db->query("insert ignore into codes(email, code, user) values('".$this->db->escape($email)."', '".$code."', '".$this->session->userdata('username')."');"); if ($query == TRUE) return TRUE; else return FALSE; } }

我尝试过没有运气的事情：


$这 - ＆GT; DB-＆GT;逃逸（$电子邮件）

mysql_real_escape_string（$电子邮件）

我不知道我哪里出错了。或者它与GoDaddy有关吗？

Answer 1

我假设你正在使用PDO。所以这个例子适用于PDO：

$stmt=$this->db->prepare("insert ignore into codes(email, code, user) ".
   " values(:email, :code, :user)");
$stmt->bindParam(":email",$email);
$stmt->bindParam(":code",$code);
$stmt->bindParam(":user",$user);

$stmt->execute();

有关详细信息，请参阅http://php.net/manual/en/pdo.prepared-statements.php。

Answer 2

我不得不重新修改你的代码但是我运行它并且它工作正常。首先是表格。您不需要提交表单和执行AJAX，执行其中一个操作。由于简单总是更好，我选择提交表格。这是带有更改的控制器和方法的表单，用于测试目的。控制器名为email_test，方法是插入电子邮件。另请注意（非常重要）onclick中的Javascript调用添加了＆＃34;返回。＆＃34;这样，如果没有电子邮件字段中的值，表单将不会提交。

<form method="post" action="email_test/insert_email">
    <div class="form-group">
        <label>Email</label>
        <input type="text" name="email" id="email" placeholder="Email" class="form-control">
    </div>
    <div class="form-group">
        <label>Waiver Code</label>
        <input type="text" name="code" id="code" placeholder="Code" class="form-control">
    </div>
    <button class="btn btn-sm btn-success" onclick="return autogen();" name="saveCode">Generate</button>
</form>

接下来是Javascript。我将其简化为仅检查电子邮件并生成代码。另请注意评论。

function autogen() {
    var randomstring = Math.random().toString(36).slice(-6);
    var date = new Date().getFullYear();
    randomstring = date + randomstring;
    randomstring = randomstring.toUpperCase();

    var email = $('#email').val();
        /*
         * This checks for a value, but it does not mean its an email.
         * You need a valid email check here too.
         */
    if (!email) {
        alert("Email is required!");
        $('#email').focus();
        /*
         * form will not submit
         */
        return false;
    } else {
        $('#code').val(randomstring);
        console.log("Email: " + email + "\nCode: " + randomstring);
        /*
         * form will submit
         */
        return true;
    }
}

最后是控制器和型号。为简洁起见，我跳过了模型，但你不应该这样做。检查对此的评论。

class Email_test extends CI_Controller {

    public function __construct() {
        parent::__construct();
    }

    public function index() {

    }

    public function insert_email() {
        /*
         * TODO here...
         * check for ajax
         * check for being sent from yourself
         * clean your input
         * return error and handle if bad input
         */

        // load your model here
        // call your model here which has the following code
        //all this code should be in a model, put here for an example.
        $query = $this->db->query("insert into codes(email, code, user) values(" . $this->db->escape($email) . ", '$code.', '" . $this->session->userdata('username') . "');");
        if ($this->db->affected_rows() > 0) {
            return TRUE;
        } else {
            return FALSE;
        }

        //handle the return from the model here
    }

}

如何从CodeIgniter中插入mysql中包含连字符/破折号的电子邮件？

2 个答案: