Question

如何针对定义响应模式的XSD文件验证SOAP响应。我正在调用的Web服务有一个XMLDocument作为输入和输出，因此不能使用WSDL进行响应模式验证。

Answer 1

我仍然需要这个（对于SOAP UI版本2.5.1有效）：文件，首选项，编辑器设置，验证响应。

Answer 2

使用脚本断言：

def project = messageExchange.modelItem.testStep.testCase.testSuite.project

def wsdlcontext = project.getInterfaceAt（0）.getDefinitionContext（）

def validator = new com.eviware.soapui.impl.wsdl.support.wsdl.WsdlValidator（wsdlcontext）;

def errors = validator.assertRequest（messageExchange，false）

断言errors.length＆lt; 1

Answer 3

您可以使用groovy脚本验证对xsd文件的响应。以下是验证的方法

import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.SchemaFactory;
import javax.xml.XMLConstants;

//Read your xsd file and get the conten into a variable like below.
def xsdContent = "Some Schema Standard";

//Take the response into another variable that you have to validate.
def actualXMLResponse = "Actual XML Response ";

//create a SchemaFactory object
def factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);

//Create a given schema object with help of factory
def schema = factory.newSchema(new StreamSource(new StringReader(xsdContent ));

//Create a validator
def validator = schema.newValidator();

//now validate the actual response against the given schema
try {
     validator.validate(new StreamSource(new StringReader(actualXMLResponse )));

} catch(Exception  e) {
     log.info (e);
     assert false;
}

我希望这会对你有所帮助： - ）

Answer 4

这对我不起作用，导致尝试不起作用

import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.SchemaFactory;
import javax.xml.XMLConstants;

//Read your xsd file and get the conten into a variable like below.
// trim - XSD SCHEME no spaces
def xsdscheme = context.expand('${Properties-XSD_Scheme_Black_and_White#XSDSchemeWhite}')
def xsdscheme2 = xsdscheme.replace(' ', '')
xsdscheme2 = xsdscheme2.replaceAll("[\n\r]", "");
log.info "RES2 TRIMED " + xsdscheme2
def xsdContent = xsdscheme2;

//Take the response into another variable that you have to validate.

Res = context.expand('${#TestCase#WhiteListDecoded}');
def Res2 = Res.replace(' ', '')
Res2 = Res2.replaceAll("[\n\r]", "");
log.info "RES2 TRIMED " + Res2
def actualXMLResponse = Res2

//create a SchemaFactory object
def factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);

//Create a given schema object with help of factory
def schema = factory.newSchema(new StreamSource(new StringReader(xsdContent ));

//Create a validator
def validator = schema.newValidator();

//now validate the actual response against the given schema
try {
     validator.validate(new StreamSource(new StringReader(actualXMLResponse )));

} catch(Exception  e) {
     log.info (e);
     assert false;
}

SOAPUI：验证对xsd模式文件的响应

4 个答案: