Question

你好，我做错了什么？

iam试图显示r.reizen与r.vertrek的日期差异为1天

有人可以提供帮助

SELECT DISTINCT b.vertrek, b.reiscode, r.bestemming, r.dagen, r.prijs
FROM boekingen b
INNER JOIN reizen r ON b.reiscode = r.reiscode
WHERE b.reiscode <> 'JH10' 
AND ((b.vertrek BETWEEN 
(SELECT MIN(DATE_SUB(vertrek, INTERVAL 1 DAY)) FROM boekingen WHERE          reiscode = 'JH10') AND 
(SELECT MIN(DATE_ADD(vertrek, INTERVAL 1 DAY)) FROM boekingen WHERE                reiscode = 'JH10')) OR 
(b.vertrek BETWEEN (SELECT MAX(DATE_SUB(vertrek, INTERVAL 1 DAY)) FROM            boekingen WHERE reiscode = 'JH10') 
AND (SELECT MAX(DATE_ADD(vertrek, INTERVAL 1 DAY)) FROM boekingen  WHERE reiscode = 'JH10')))
ORDER BY 1

Msg 102, Level 15, State 1, Line 6
Incorrect syntax near '1'.
Msg 102, Level 15, State 1, Line 7
Incorrect syntax near '1'.
Msg 102, Level 15, State 1, Line 8
Incorrect syntax near '1'.
Msg 102, Level 15, State 1, Line 9
Incorrect syntax near '1'.

Answer 1

简单回答：您正在使用Microsoft SQL Server引擎的DATE_SUB的MySQL语法。对于猜测的人来说，这是一个Microsoft SQL错误。

 Msg 102, Level 15, State 1

您正在使用的日期功能是：

DATE_SUB(vertrek, INTERVAL 1 DAY))
DATE_ADD(vertrek, INTERVAL 1 DAY)) FROM

Microsoft变种是：

DATEADD(DAY, -1, vertrek)
DATEADD(DAY, 1, vertrek)

Accepteer dit antwoord en punten toekennen，bedankt。

Answer 2

除了修复日期算术之外，如果没有@@toolbar = nil子句中的子查询，您的查询将更容易阅读。将摘要移动到WHERE子句很简单：

FROM

SQL Server DATE_DIFF INTERVAL？

2 个答案: