我正在使用ui.bootstrap.timepicker通过用户互动创建和更新数据。
Timepicker适用于创建数据,但它不与ng模型绑定。
以下是传递给Timepicker的数据的示例JSON数组:
{
"sort":1,
"name":"Store Timings",
"_id":"55b78a8658d3060e004fe9f2",
"delivery":[
{
"open":"10:30",
"close":"20:00",
"leadTime":"45",
"interval":"15",
"message":"Accepting delivery orders",
"_id":"55b78a8658d3060e004fe9f3",
"isOpen":true
}
],
"pickup":[
{
"open":"09:30",
"close":"20:30",
"leadTime":"30",
"interval":"15",
"message":"Accepting takeot orders",
"_id":"55b78a8658d3060e004fe9f4",
"isOpen":true
}
],
"store":[
{
"open":"9:30 AM",
"close":"10:30 PM",
"message":"We are Open!",
"_id":"55b78a8658d3060e004fe9f5",
"isOpen":true
}
],
"isOnlineOrderOpen":true
}
根据上面的代码,我尝试将ng-value渲染到Timepicker
以下是HTML代码:
<timepicker ng-model="sunday.store[0].open" hour-step="1" minute-step="15" show-meridian="true" ></timepicker>
<timepicker ng-model="sunday.store[0].close" hour-step="1" minute-step="15" show-meridian="true" ></timepicker>
答案 0 :(得分:3)
Timepicker期望您传入Date对象,而不是字符串。
来自Timepicker documentation
ng-model:提供时间状态的Date对象。
我正在使用MomentJS将日期从字符串格式化为Date对象。
请参阅MomentJS parse documentation
如果需要,您可以使用相同的库将时间转换回字符串。