Question

我刚开始将Dapper用于我的项目和我无法找到一种方法将对象作为参数传递给Dapper.Net

是否有任何方法将对象作为参数传递，然后Dapper会将对象属性映射到参数化的S.Q.L？

而不是使用它：

public class Product
{
    public int ProductID { get; set; }
    public string Name { get; set; }

    public string Description { get; set; }
    public decimal Price { get; set; }
    public string Category { get; set; }
}

static void Main(string[] args)
{
    Product product = new Product()
    {
        Name = "DHS - 3 Star Ball",
        Price = 11,
        Category = "Table Tennis",
        Description = "ITTF - Approved Table Tennis Ball",
        ProductID = 1
    };

    using(IDbConnection dbConnection = ...ConnectionStrings)
    {
        string query = "INSERT INTO Products (Properties here) VALUES (@Properties)";
        dbConnection.Execute(query, ...product.properties here sample: product.ProductID); //<------- Is there any substitute to this?
    }

}

Answer 1

我不认为你只能使用Dapper.Contrib来做到这一点。 Dapper.Contrib包含有用的扩展，如

T Get<T>(id);
IEnumerable<T> GetAll<T>();
int Insert<T>(T obj);
int Insert<T>(Enumerable<T> list);
bool Update<T>(T obj);
bool Update<T>(Enumerable<T> list);
bool Delete<T>(T obj);
bool Delete<T>(Enumerable<T> list);
bool DeleteAll<T>();

有关详细信息，请查看here

在Dapper.contrib的帮助下，你可以做到这样的事情，甚至不用写sql查询并传递参数

 class Program
    {
        static void Main(string[] args)
        {
            var usr = new User()
            {

                Email = "testmail",
                Name = "testname"
            };

            var connection = System.Configuration.ConfigurationManager.ConnectionStrings["MainDb"].ConnectionString;
            using (IDbConnection dbConnection = new SqlConnection(connection))
            {
            dbConnection.Open();
                long insert = dbConnection.Insert<User>(usr);
            }
        }
    }

    [Table("[User]")]
    public class User
    {
        [Key]
        public int Id { get; set; }
        public string Name { get; set; }
        public string Email { get; set; }

    }

如何使用dapper.net传递params中对象的整个属性

1 个答案: