PHP：更新查询不起作用

Question

以下是php代码：

<?php 
    if (isset($_POST['update-post'])) {

                    $post_title_update= $_POST['post-title'];
                    $post_category_update= $_POST['post-category-id'];
                    $post_author_update=$_POST['post-author'];
                    $post_content_update= $_POST['post-content'];
                    $post_tags_update= $_POST['post-tags'];
                    $post_comment_update= $_POST['post-comment-count'];
                    $post_status_update= $_POST['post-status'];       

                    $post_image_update=  $_FILES['image']['name'];
                    $post_image_temp = $_FILES['image']['tmp_name'];

                    move_uploaded_file($post_image_temp, "images/$post_image_update");

                    $update_query="UPDATE post set "; 
                    $update_query.="post_category_id= '{$post_category_update}', ";         
                    $update_query.="post_title= '{$post_title_update}', ";                 
                    $update_query.="post_author= '{$post_author_update}', "; 
                    $update_query.="post_date= now(), ";         
                    $update_query.= "post_image ='{$post_image_update}', "; 
                    $update_query.="post_content= '{$post_content_update}', "; 
                    $update_query.="post_tags= '{$post_tags_update}', "; 
                    $update_query.="post_comment= '{$post_comment_update}', "; 
                    $update_query.="post_status= '{$post_status_update}' "; 
                    $update_query.="WHERE  post_id={$id} ";

                    //echo $update_query;
                    $update_query_result= mysqli_query($connnect, $update_query);
                    if ($update_query_result) {
                        echo 'Record Updated !';
                    }
                    else{
                        echo mysqli_error($connect);
                    }

        }        

    ?>

Html表格：

 [![<form action="" method="post" enctype="multipart/form-data">

        <div class="form-group">
            <label for="post-title">Post Title</label>
            <input type="text" name="post-title" class="form-control" value="<?php echo $post_title;?>">
        </div>

        <div class="form-group">
            <label for="post-category-id">Post Category </label>
            <select class="form-control" name="post-category-id">
                <?php 
                    $querycategory= "SELECT * FROM category"; 
                    $select_category= mysqli_query($connect, $querycategory);
                    while ($categories = mysqli_fetch_assoc($select_category)) {
                        echo  "<option>{$categories\['cat_title'\]}</option>";
                    }
                ?>
            </select>

        </div>

        <div class="form-group">
            <label for="post-author">Post Author</label>
            <input type="text" name="post-author" class="form-control" value="<?php echo $post_author;?>">
        </div>

        <div class="form-group">

            <label for="post-image">Upload image </label>
            <input type="file" name="image">        
        </div>

        <div class="form-group">
            <label for="post-content">Post Content</label>
            <textarea class="form-control" rows="4" name="post-content" cols="30" ><?php echo $post_content;?> </textarea>


        </div>

        <div class="form-group">
            <label for="post-tags">Post Tags</label>
           <input type="text" name="post-tags" class="form-control" value="<?php echo $post_tags;?>">
        </div>

        <div class="form-group">
            <label for="post-comment-count">Comment Count</label>

           <input type="text" name="post-comment-count" class="form-control" value="<?php echo $post_comment;?>">
        </div>

        <div class="form-group">
            <label for="post-status"></label>
           <input type="text" name="post-status" class="form-control" value="<?php echo $post_status;?>">
        </div>

        <input type="submit" name="update-post" value="Update Post" class="btn btn-primary">
    </form>

现在，当我点击更新时，它既没有出现任何错误也没有更新数据库，请帮助它

Answer 1

$update_query_result= mysqli_query($connnect, $update_query);
                                   ^^^^^^^^^ TYPO (should be $connect)
if ($update_query_result) {
    echo 'Record Updated !';
}
else{
    echo mysqli_error($connect); 
                      ^^^^^^^^ Correct form of the word is used here.
}

您在链接的变量名称中输入了拼写错误。除此之外，您很容易受到SQL注入攻击。请阅读并考虑使用准备好的查询。