我正在尝试使用带有核心/匹配和核心/类型的clojure来解决this SICP练习。
我跟随Jeanine Adkisson的"Variants are Not Unions"谈话。
这是我到目前为止所得到的:
(ns sicp.chapter2_ex29
(:require [clojure.core.typed :as t]
[clojure.core.match :refer [match]]))
; Type definitions
(t/defalias Mobile '{:left Branch, :right Branch})
(t/defalias Weight Number)
(t/defalias Structure
(t/U '[(t/Value :weight) Weight]
'[(t/Value :mobile) Mobile]))
(t/defalias Branch '{:length Number, :structure Structure})
; Constructors
(t/ann make-mobile [Branch Branch -> Mobile])
(defn make-mobile [left right]
{:left left :right right})
(t/ann make-branch [Number Structure -> Branch])
(defn make-branch [length structure]
{:length length :structure structure})
; Getters
(t/ann left-branch [Mobile -> Branch])
(defn left-branch [mobile]
(:left mobile))
(t/ann right-branch [Mobile -> Branch])
(defn right-branch [mobile]
(:right mobile))
(t/ann branch-length [Branch -> Number])
(defn branch-length [branch]
(:length branch))
(t/ann branch-structure [Branch -> Structure])
(defn branch-structure [branch]
(:structure branch))
; Total weight
(t/ann total-weight [Mobile -> Number])
(defn total-weight [mobile]
(t/letfn> [structure-weight :- [Structure -> Number]
(structure-weight [structure]
(do
(println (str "structure -> " structure))
(println (str "structure0 -> " (get structure 0)))
(println (str "structure1 -> " (get structure 1)))
(match structure
[:weight weight] weight
[:mobile mobile] (total-weight mobile))))
branch-weight :- [Branch -> Number]
(branch-weight [branch]
(structure-weight (branch-structure branch)))]
(let
[left (branch-weight (left-branch mobile))
right (branch-weight (right-branch mobile))]
(do
(println (str "left ->" left))
(println (str "right ->" right))
(+ left right)))))
(t/ann mobile1 Mobile)
(def mobile1 (make-mobile
(make-branch 3 [:weight 4])
(make-branch 5 [:weight 2])))
(total-weight mobile1) ; <- works as expected = 6
(t/ann mobile2 Mobile)
(def mobile2 (make-mobile
(make-branch 3 [:weight 4])
(make-branch 5 [:mobile (make-mobile
(make-branch 2 [:weight 3])
(make-branch 4 [:weight 2]))])))
(total-weight mobile2) ; <- throws java.lang.IllegalArgumentException: No matching clause: [:mobile {:left {:length 2, :structure [:weight 3]}, :right {:length 4, :structure [:weight 2]}}]
结构类型是一个变体:它是一个权重,它只是一个数字(它的形式为[:weight weight],其中权重是一个数字)或者它是一个移动(它的形式为[:mobile]移动]移动是移动类型的东西。)
它进行类型检查,总权重函数适用于简单的输入:由两个权重组成的移动设备。
但正如您所看到的那样,对于具有移动分支的移动设备而言,它失败了。
由于某种原因,它与[:mobile mobile]案例不匹配。我知道自己做错了什么?
答案 0 :(得分:1)
问题似乎是
中的标识符mobile
(match structure
[:weight weight] weight
[:mobile mobile] (total-weight mobile))))
...已作为封闭函数定义中的参数绑定:
(defn total-weight [mobile]
... )
将match
表单更改为
(match structure
[:weight w] w
[:mobile m] (total-weight m))))
...删除错误。
规则似乎是:
如果绑定了
match
模式中的名称,则不会在本地反弹。它 被解释为它的主导价值。
我不得不说我只是偶然发现了这个错误。我希望本地绑定优先,但事实并非如此。
备注强>
match
表达式的语法不遵循the documentation,这需要......
(match [structure]
[[:weight w]] w
[[:mobile m]] (total-weight m))
...但您的缩写版本也可以。
Clojure成语是尽可能使用标准数据结构 - 特别是地图 - 避开访问函数和构造函数。通过这种方式,我们可以编写类似
的内容; Total weight
(declare structure-weight)
(t/ann total-weight [Mobile -> Number])
(defn total-weight [mobile]
(match [mobile]
[{:left bl, :right br}]
(apply + (map
(comp structure-weight :structure)
[bl br]))))
(t/ann structure-weight [Structure -> Number])
(defn structure-weight [structure]
(match [structure]
[[:weight w]] w
[[:mobile m]] (total-weight m)))