Question

下面的数据框显示了不同的公司，他们收到的产品以及他们收到的日期。我想要做的是让“Time.Rank”列反映同一Account.Name中Received.Date发生的时间顺序（从最早 - 最晚的日期）。

df <- data.frame(
      Company = c("Walmart", "Walmart", "Walmart", "Walmart", "Walmart", "Staples", "Staples"),
      Product.Name = c("tape", "flower", "tape", "chocolate", "pencil", "pencil", "tape"),
      Received.Date = c("2013-09-30", "2013-09-30", "2015-05-08", "2015-05-08", "2015-05-08", "2014-12-12", "2014-12-17"),
      Time.Rank = c("1", "2", "3", "4", "5", "1", "2"))

我的问题是关于Time.Rank列。我如何得到Time.Rank专栏：

df <- data.frame %>%
  mutate(Time.Rank = row_number(Account.Name))

现在的问题是，即使第1-2行和第3-5行都有相同的Received.Date，它们仍然有不同的排名。我希望具有相同Received.Date的行具有排名。即第1行和第2行都应该有Time.Rank = 1，第3-5行应该有Time.Rank = 2.所以这个：

 df <- data.frame(
          Company = c("Walmart", "Walmart", "Walmart", "Walmart", "Walmart", "Staples", "Staples"),
          Product.Name = c("tape", "flower", "tape", "chocolate", "pencil", "pencil", "tape"),
          Received.Date = c("2013-09-30", "2013-09-30", "2015-05-08", "2015-05-08", "2015-05-08", "2014-12-12", "2014-12-17"),
          Time.Rank = c("1", "1", "2", "2", "2", "1", "2"))

Answer 1

我认为您正在寻找的是dense_rank

df %>% group_by(Company) %>% mutate(Time.Rank = dense_rank(Received.Date))


  Company Product.Name Received.Date Time.Rank
1 Walmart         tape    2013-09-30         1
2 Walmart       flower    2013-09-30         1
3 Walmart         tape    2015-05-08         2
4 Walmart    chocolate    2015-05-08         2
5 Walmart       pencil    2015-05-08         2
6 Staples       pencil    2014-12-12         1
7 Staples         tape    2014-12-17         2

如何给重复行添加相同的排名？

1 个答案: