var filterModel = new List<FilterModel>()
{
new FilterModel {Price = 1},
new FilterModel {Price = 1},
new FilterModel {Price = 15},
new FilterModel {Price = 20},
new FilterModel {Price = 410},
new FilterModel {Price = 9511},
new FilterModel {Price = 9511},
new FilterModel {Price = 252},
new FilterModel {Price = 555},
new FilterModel {Price = 602}
};
var priceList = new List<PriceList>
{
new PriceList{MinPrice = 0,MaxPrice = 30},
new PriceList{MinPrice = 70,MaxPrice = 130},
new PriceList{MinPrice = 200,MaxPrice = 250},
new PriceList{MinPrice = 400,MaxPrice = 600},
//etc.etc. continue...
};
我有2个型号。我试图使用LINQ。我的代码正在运行。 什么是最短(最干净)的方法呢?
var newFilterModel = new List<FilterModel>();
foreach (var t in priceList)
{
newFilterModel.AddRange(filterModel
.Where(x => x.Price > t.MinPrice && x.Price < t.MaxPrice)
.ToList());
}
var distinctNewFilterModel = newFilterModel.Select(p=>new { p.Price})
.Distinct().ToList();
答案 0 :(得分:2)
我不知道这是否短暂&amp;对你来说足够干净,但是......
var newFilterModel = filterModel
// Select just the price
.Select(f => f.Price)
// Remove duplicates
.Distinct()
// Find prices in the price list
.Where(price => priceList
.FindIndex(p => p.MinPrice <= price && price <= p.MaxPrice) != -1)
// Turn the price back into a FilterModel object
.Select(price => new FilterModel { Price = price })
// Turn the entire result into a new List<FilterModel>
.ToList();
newFilterModel.ForEach(newF => Console.WriteLine(newF.Price));
结果:
1
15
20
410
555
如果您要在IEquatable<>
课程中实施FilterModel
,请执行以下操作:
public class FilterModel : IEquatable<FilterModel>
{
public int Price { get; set; }
public bool Equals(FilterModel other)
{
//Check whether the compared object is null.
if (ReferenceEquals(other, null)) return false;
//Check whether the compared object references the same data.
if (ReferenceEquals(this, other)) return true;
//Check whether the products' properties are equal.
return other.Price == Price;
}
public override int GetHashCode()
{
//Get hash code for the Price field.
return Price.GetHashCode();
}
}
然后您的Linq
语句变短:
var newFilterModel = filterModel
// Remove duplicates
.Distinct()
// Find prices in the price list
.Where(filterPrice => priceList
.FindIndex(price => price.MinPrice <= filterPrice.Price && filterPrice.Price <= price.MaxPrice) != -1)
// Turn the entire result into a List<FilterModel>
.ToList();
newFilterModel.ForEach(p => Console.WriteLine(p.Price));
结果:
1
15
20
410
555
答案 1 :(得分:1)
您可以像这样使用cross join并获取IEnumerable<FilterModel>
var distinctNewFilterModel = from filter in filterModel
from price in priceList
where filter.Price > price.MinPrice && filter.Price < price.MaxPrice
group filter by filter.Price into groupped
select groupped.First();
但不确定这个最短和最干净比你有