Question

我尝试创建一个SecUser域对象，其中包含UserGroup个对象的集合。每个UserGroup都应该有一个SecUser类型的创建者。 UserGroup还包含SecUsers的集合（例如，Facebook风格应用上的创建者朋友集合）。到目前为止，我有以下域类...

class SecUser implements Serializable {
  static constraints = {
    ....
    usergroups nullable: true
  }
  static mapping = {
    ...
    usergroups cascade: 'all-delete-orphan'
  }
  static hasMany = [
    ...
    usergroups: UserGroup
  ]
}

class UserGroup {
  SecUser creator;
  static belongsTo = SecUser;
  static hasMany = [
    members : SecUser
  ]
  static constraints = {
    creator nullable: false
    members nullable: true, maxSize: 100
  }
}

在Bootstrap.groovy中，我尝试创建一些SecUser和UserGroup个对象......

def secuser = new SecUser(username: "username", password: "password");
def group1 = new UserGroup(title: "Friends", description: "friends");
def group3 = new UserGroup(title: "Colleagues", description: "colleagues");
secuser.addToUsergroups(group1);
secuser.addToUsergroups(group2);

但是我收到的错误是......

ERROR spi.SqlExceptionHelper  - NULL not allowed for column "USER_GROUP_ID"; SQL statement:
insert into sec_user_usergroups (sec_user_id, creator_id) values (?, ?) [23502-176]
Error |
2015-07-28 11:04:49,208 [localhost-startStop-1] ERROR context.GrailsContextLoaderListener  - Error initializing the application: Hibernate operation: could not execute statement; SQL [n/a]; NULL not allowed for   column "USER_GROUP_ID"; SQL statement:
insert into sec_user_usergroups (sec_user_id, creator_id) values (?, ?) [23502-176]; nested exception is org.h2.jdbc.JdbcSQLException: NULL not allowed for column "USER_GROUP_ID"; SQL statement:
insert into sec_user_usergroups (sec_user_id, creator_id) values (?, ?) [23502-176]
Message: Hibernate operation: could not execute statement; SQL [n/a]; NULL not allowed for column "USER_GROUP_ID"; SQL statement:
insert into sec_user_usergroups (sec_user_id, creator_id) values (?, ?) [23502-176]; nested exception is org.h2.jdbc.JdbcSQLException: NULL not allowed for column "USER_GROUP_ID"; SQL statement:
insert into sec_user_usergroups (sec_user_id, creator_id) values (?, ?) [23502-176]

我想该程序告诉我它无法完成addToUsergroups操作，因为UserGroup还没有id（因为它没有＆{} ＃39; t得救了）。但有没有办法让addToUsergroups操作在没有id的情况下完成？（因为UserGroup不应该在没有SecUser的情况下创建。或者我的域对象的设计有问题吗？

提前致谢！

Answer 1

我猜你的UserGroup表中的PK列叫做USER_GROUP_ID，如果这是你的所有代码，你就不会说任何关于它的内容，并且你在数据库中有一个约束，它不允许你把它留空。因此，您必须更改UserGroup id ，指定以不同方式调用 PK 列。

class UserGroup {
  SecUser creator;
  static belongsTo = SecUser;
  static hasMany = [
    members : SecUser
  ]

  static mapping = {
    id column: 'user_group_id'
  }

  static constraints = {
    creator nullable: false
    members nullable: true, maxSize: 100
  }
}

希望它有所帮助。

Grails域错误：列不允许NULL＆＃34; USER_GROUP_ID＆＃34;

1 个答案: