Question

我有一个类PostedJobHistory（片段）：

public class PostedJobHistory extends Fragment {
    String employerName;
    private List<ParseObject> jobDetails;
    Context context;
    public PostedJobHistory() {}
    public PostedJobHistory(Context context, String employerName) {
        this.context = context;
        this.employerName = employerName;
    }
    ListView listViewJobHistory;
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        View jobsView = inflater.inflate(R.layout.fragment_posted_job_history, container, false);
        listViewJobHistory = (ListView) jobsView.findViewById(R.id.listViewJobHistory);

        if(jobDetails==null){
            jobDetails=new ArrayList<ParseObject>();
            EmployerHistory jobsQuery=new EmployerHistory();
            jobDetails = jobsQuery.getJobHistory(employerName);
        }

        listViewJobHistory.setAdapter(new TimelineList(context, jobDetails));

        return jobsView;
    }
}

对于适配器，我将此类放在与上面相同的.java文件中：

class TimelineList extends BaseAdapter {
    private List<ParseObject> elements;
    Context mContext;
    public TimelineList(Context mContext, List<ParseObject> elements) {
        this.mContext = mContext;
        this.elements = elements;
    }


    @Override
    public int getCount() {
        return elements.size();
    }

    @Override
    public ParseObject getItem(int position) {
        return elements.get(position);
    }

    @Override
    public long getItemId(int position) {
        return position;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {

//this line is giving runtime exception
            LayoutInflater inflater = ((Activity)mContext).getLayoutInflater();
            View row;
            row = inflater.inflate(R.layout.job_history_listitem, parent, false);
            TextView title, detail;
            title = (TextView) row.findViewById(R.id.title);
            detail = (TextView) row.findViewById(R.id.detail);
            title.setText(getItem(position).get("JobName").toString());
            title.setMovementMethod(LinkMovementMethod.getInstance());
            detail.setText(getItem(position).get("updatedAt").toString());
            return (row);
        }
    }

07-28 02：06：12.424 17392-17392 / com.example.ankit.job_depot E / AndroidRuntime：致命异常：主要处理：com.example.ankit.job_depot，PID：17392 java.lang.ClassCastException：android.app.Application无法强制转换为android.app.Activity 在com.example.ankit.job_depot.TimelineList.getView（PostedJobHistory.java:80）在android.widget.AbsListView.obtainView（AbsListView.java:2347）在android.widget.ListView.measureHeightOfChildren（ListView.java:1270）在android.widget.ListView.onMeasure（ListView.java:1182）在android.view.View.measure（View.java:17547）在android.widget.RelativeLayout.measureChildHorizontal（RelativeLayout.java:727）在android.widget.RelativeLayout.onMeasure（RelativeLayout.java:463）在android.view.View.measure（View.java:17547）在android.support.v4.view.ViewPager.onMeasure（ViewPager.java:1455）在android.view.View.measure（View.java:17547）在android.view.ViewGroup.measureChildWithMargins（ViewGroup.java:5535）

here给出Context不能被转换为Activity，因为它不是它的子类。我不知道如何解决这个问题。

Answer 1

您必须尝试将getApplicationContext()而不是Activity传递给fragment的构造函数。尝试传递活动实例而不是应用程序上下文。

要PostedJobHistory constructor，请使用this

传递父活动实例

Answer 2

这是错误的

public PostedJobHistory(Context context, String employerName) {
    this.context = context;
    this.employerName = employerName;
}

片段应该没有参数构造函数

其次，您可以使用getActivity()获取活动的上下文 onCreateView

listViewJobHistory.setAdapter(new TimelineList(getActivity(), jobDetails));

然后在适配器的构造函数中

LayoutInflate inflater;
public TimelineList(Context mContext, List<ParseObject> elements) {
    inflater = LayoutInflater.from(mContext);
    this.elements = elements;
}

如果您需要将数据从活动传递到片段

Send data from activity to fragment in android

此外，您应该使用ViewHolder模式

http://developer.android.com/training/improving-layouts/smooth-scrolling.html

注意： Fragment的所有子类必须包含公共无参数构造函数。

来源：

http://developer.android.com/reference/android/app/Fragment.html

Answer 3

您正在将Context转换为Activity，这就是您收到错误的原因。

请在构造函数的参数中传递Activity而不是Context

Activity mActivity ;
    public TimelineList(Activity mActivity, List<ParseObject> elements) {
        this.mActivity= mActivity;
        this.elements = elements;
    }

BaseAdapter getLayoutInflater给出运行时异常

3 个答案: