Question

我正在运行此查询到SQL Server 2008+，但它不适用于SQL Server 2000。我需要这个来执行。

WITH CTE AS ( 
    SELECT
        custnum,
        custname,
        RN = ROW_NUMBER() OVER( PARTITION BY custnum, custname ORDER BY custnum )
    FROM
        cust
)
SELECT
    *
FROM
    CTE
WHERE RN > 1

非常感谢你的帮助！

Answer 1

看看是否有效

select custnum,custname from
(
select (select count(*) from cust as t1 where t1.custnum<=t2.custnum) as sno,
 custnum,custname from cust as t2
) as t
where sno>1

Answer 2

在SQL Server 2005之前，此问题域通过在#temp表中按顺序插入并使用IDENTITY列来生成序列号来解决。这将解决RANK()和ROW_NUMBER()要求。

E.g：

    -- Create empty temp table
    SELECT custnum, custname, IDENTITY(INT, 1, 1) as RN
    INTO #cust
    FROM cust
    WHERE 0 = 1

    -- Populate with ORDER BY, to generate ascending RN
    INSERT INTO #cust
        (custnum, custname)
    SELECT
        custnum, custname
    FROM 
        cust
    ORDER BY
        custnum, custname

此时，您可以查询MIN()每个custnum / custname分组，并在使用CTE时使用它。

然而...... ROW_NUMBER()真的是你想要的吗？好像你想要RANK()，而不是ROW_NUMBER()。

如何将此查询转换为SQL Server 2000语法

2 个答案: