Question

使用jquery

获取锚点的值

我的问题是如何使用jquery获取值33。

提前完成。

Answer 1

$('.paginate_button').last().text()

看起来你已经更新了问题，这使得答案不正确，所以下面是我更新的答案。

$('#myTable_reports_view_paginate span > a.paginate_button').last().text()

Answer 2

使用 :last 选择器，以避免next使用 :not()

alert($('a.paginate_button:not(.next):last').text())

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="dataTables_paginate paging_simple_numbers" id="myTable_reports_view_paginate">
  <a class="paginate_button previous disabled" aria-controls="myTable_reports_view" data-dt-idx="0" tabindex="0" id="myTable_reports_view_previous">&lt;&lt;</a>
  <span>
                        <a class="paginate_button current" aria-controls="myTable_reports_view" data-dt-idx="1" tabindex="0">1</a>
                        <a class="paginate_button " aria-controls="myTable_reports_view" data-dt-idx="2" tabindex="0">2</a>
                        <a class="paginate_button " aria-controls="myTable_reports_view" data-dt-idx="3" tabindex="0">3</a>
                        <a class="paginate_button " aria-controls="myTable_reports_view" data-dt-idx="4" tabindex="0">4</a>
                        <a class="paginate_button " aria-controls="myTable_reports_view" data-dt-idx="5" tabindex="0">5</a>
                        <span class="ellipsis">…</span>
  <a class="paginate_button " aria-controls="myTable_reports_view" data-dt-idx="6" tabindex="0">33</a>
  </span>
  <a class="paginate_button next" aria-controls="myTable_reports_view" data-dt-idx="7" tabindex="0" id="myTable_reports_view_next">&gt;&gt;</a>
</div>

您还可以使用last()和not()

alert($('a.paginate_button').not('.next').last().text())

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="dataTables_paginate paging_simple_numbers" id="myTable_reports_view_paginate">
  <a class="paginate_button previous disabled" aria-controls="myTable_reports_view" data-dt-idx="0" tabindex="0" id="myTable_reports_view_previous">&lt;&lt;</a>
  <span>
                        <a class="paginate_button current" aria-controls="myTable_reports_view" data-dt-idx="1" tabindex="0">1</a>
                        <a class="paginate_button " aria-controls="myTable_reports_view" data-dt-idx="2" tabindex="0">2</a>
                        <a class="paginate_button " aria-controls="myTable_reports_view" data-dt-idx="3" tabindex="0">3</a>
                        <a class="paginate_button " aria-controls="myTable_reports_view" data-dt-idx="4" tabindex="0">4</a>
                        <a class="paginate_button " aria-controls="myTable_reports_view" data-dt-idx="5" tabindex="0">5</a>
                        <span class="ellipsis">…</span>
  <a class="paginate_button " aria-controls="myTable_reports_view" data-dt-idx="6" tabindex="0">33</a>
  </span>
  <a class="paginate_button next" aria-controls="myTable_reports_view" data-dt-idx="7" tabindex="0" id="myTable_reports_view_next">&gt;&gt;</a>
</div>

Answer 3

Try this
$('.paginate_button:contains("33")').text()

使用jquery获取锚的值

3 个答案: