用find命令获取下一行

Question

我用with data as ( select p.person_id,TRUNC ((SYSDATE - p.birth_date) / 365.25, 0) AS age from person p ) select '30 or below' as stat, sum(case when age between 0 and 30 then 1 else 0 end) as count from data union all select '31 to 60' as stat, sum(case when age between 31 and 60 then 1 else 0 end) as count from data union all select '31 to 130' as stat, sum(case when age between 31 and 130 then 1 else 0 end) as count from data ; 执行了一个包含cmd指令的python文件来获取结果。

现在，结果显示为

'name.py dir'

我不想看到进度，只是想看到最后的结果，这是最后两行。

所以我尝试了这条指令.... .... processing .... .... ============ result 1 2 3 x.xxx <---- this is what I want to get

它显然找到'name.py dir | find 'result''行，但没有显示真实结果'x.xxx'。

结果只是，

result

如何使用result 1 2 3 指令获取find的下一行？

Answer 1

尝试使用grep

grep -A 1结果

来自man grep：    -A NUM， - after-context = NUM               匹配行后打印NUM行尾随上下文。