Question

假设我有一个以下查询（我的实际查询的一部分），它检索该人的person_id和年龄：

select p.person_id,TRUNC ((SYSDATE - p.birth_date) / 365.25, 0) AS age
from person p

现在，在达到这个年龄后，我希望得到每个年龄段的人数，如：

 group                count
age <=5                100
age >5 and age <=10    50
 age > 10              15
   ...                ...

我可以使用group by子句来计算个人年龄。但如何在两个年龄之间计算？

有人可以告诉我我可以这样做的方式吗？

您可以使用以下数据供您参考：

所以结果应该是：

   group      count
   age < =5     1
   >5 & <=10    3
   > 10         2

Answer 1

首先，您的年龄计算不正确。你几乎肯定想要测量两个日期之间的月份，而不是希望除以365.25足够接近

trunc( months_between( sysdate, p.birth_date )/ 12 )

其次，如果您想按范围分组，您只需要在case语句中选择范围并按

分组

SELECT (case when age <= 5
             then 'age <= 5'
             when age > 5 and age <= 10
             then 'age > 5 and age <= 10'
             else 'age > 10'
         end) bucket,
       count(*)
  FROM( SELECT trunc( months_between( sysdate, p.birth_date )/ 12 ) age
          FROM person p )
 GROUP BY (case when age <= 5
                then 'age <= 5'
                when age > 5 and age <= 10
                then 'age > 5 and age <= 10'
                else 'age > 10'
            end)

Answer 2

假设您已经有年龄的计算值。您可以使用 CASE 表达式和 GROUP BY 不同年龄段。

例如，

SQL> WITH data(person_id, age) AS(
  2  SELECT 1,  3 FROM dual UNION ALL
  3  SELECT 2,  4 FROM dual UNION ALL
  4  SELECT 3,  8 FROM dual UNION ALL
  5  SELECT 4,  9 FROM dual UNION ALL
  6  SELECT 5, 15 FROM dual UNION ALL
  7  SELECT 6, 25 FROM dual UNION ALL
  8  SELECT 7, 32 FROM dual UNION ALL
  9  SELECT 8, 44 FROM dual UNION ALL
 10  SELECT 9, 67 FROM dual UNION ALL
 11  SELECT 10, 75 FROM dual
 12  )
 13  SELECT (
 14    CASE
 15      WHEN age <= 5
 16         THEN 'age <= 5'
 17      WHEN age > 5 AND age <= 10
 18         THEN 'age > 5 and age <= 10'
 19      WHEN age > 10 AND age <= 30
 20         THEN 'age > 10 and age <= 30'
 21      ELSE 'age > 30'
 22    END) age_group,
 23    COUNT(*)
 24  FROM data
 25  GROUP BY (
 26    CASE
 27      WHEN age <= 5
 28         THEN 'age <= 5'
 29      WHEN age > 5 AND age <= 10
 30         THEN 'age > 5 and age <= 10'
 31      WHEN age > 10 AND age <= 30
 32         THEN 'age > 10 and age <= 30'
 33      ELSE 'age > 30'
 34    END)
 35  /

AGE_GROUP                COUNT(*)
---------------------- ----------
age <= 5                        2
age > 10 and age <= 30          2
age > 5 and age <= 10           2
age > 30                        4

SQL>

如果您没有年龄范围，则可以使用解码对确切年龄进行硬编码。

Answer 3

您可能想要这样做：

dot_prod_total = sum(np.outer(cell[key], patient[key]).flat for key in cell) 


dot_prod_total =

Pat_1&LN18   Pat_1&22RV1   Pat_1&DU145   Pat_2&LN18   ...
8            10            12            16

示例：http://sqlfiddle.com/#!4/8c9ae4/13

如何在Oracle数据库中使用SQL查询获取基于年龄组的人数？

3 个答案: