Question

var details = [{
    "Name": "Bhavani",
        "Phone No": ["123456", "123456"],
        "Email Id": ["mamata@gmail.com", "mamata@yahoo.com"],
        "Birthday": "21/16/22/33"
}, {
    "Name": "Mamata",
        "Phone No": ["123456", "123456"],
        "Email Id": ["mamata@gmail.com", "mamata@yahoo.com"],
        "Birthday": "21/16/22/33"
}];

function add() {
    localStorage.setItem('contacts', JSON.stringify(details));
    str = localStorage.getItem("contacts");
}

function removeItems(){
  var s = localStorage.removeItem("contacts");
  alert(s);
}

JSFiddle demo

如何只删除数组中的一个元素而不删除整个本地存储？

Answer 1

我在评论下的评论代码示例 - 从Mamata删除电子邮件ID：

var details = JSON.parse(localStorage.getItem('contacts'));
details.filter(function(e) {
  return e.Name === "Mamata"
}).forEach(function(element) {
  delete element["Email Id"];
});
localStorage.setItem('contacts', JSON.stringify(details));

编辑：如果您要删除整个记录而不是其中的字段，则应执行此操作：

var details = JSON.parse(localStorage.getItem('contacts'));
details = details.filter(function(e) {
  return e.Name !== "Mamata"
});
localStorage.setItem('contacts', JSON.stringify(details));

Answer 2

localStorage.setItem("contacts",localStorage.getItem("contacts").split(',').splice(...));

如何从本地存储中只删除数组中的一个元素？

2 个答案: