我正在尝试读取两个文件，匹配它们，然后打印另一个文件。但我一直得到这个Foo(dog(name));
。我不知道如何解决它，有人可以帮助我吗？这是我的代码：
import React from 'react';
import { Link } from 'react-router';
import ReactLogo from 'elements/ReactLogo';
import mui, { RaisedButton } from 'material-ui';
let ThemeManager = new mui.Styles.ThemeManager();
class YourAwesomeComponent extends React.Component
{
static get childContextTypes()
{
return { muiTheme: React.PropTypes.object };
}
getChildContext()
{
return { muiTheme: ThemeManager.getCurrentTheme() };
}
render ()
{
return (
<div>
<RaisedButton />
</div>
)
}
};
module.exports = YourAwesomeComponent;
答案 0 :(得分：1)
问题在于你不算数。您错过了3个，4个或7个字符的数字行。我们来看看你的代码，方法ThreeCharacters：
public static int ThreeCharacters(String s2) throws IOException {
Scanner in = new Scanner(new File(s2));
int count = 0;
while (in.hasNextLine()) {
in.nextLine();
if (in.nextLine().length() == 3) {
count++;
}
}
in.close();
return count;
}
in.nextLine()读取并跳过一行，然后if (in.nextLine().length() == 3)再次读取并跳过另一行。最后，您只检查一行超过两行。建议是删除没有做任何事情的in.nextLine()，我猜。如果出于任何原因你故意将它放在Store3Words中，那么你也只需要处理两行以上的一行。这将解决ArrayIndexOutOfBoundsException，但您的代码中可能还有其他问题，因为作为初学者，您没有遵循编程中应遵循的路径：编写一个方法，测试并确保它正常工作然后转到下一个方法。
总而言之，我建议您编写一个计数方法和一个存储方法，您的代码可以变得如此紧凑：
import java.io.IOException;
import java.util.Scanner;
import java.io.File;
import java.io.FileWriter;
import java.io.PrintWriter;
class TestApp{
final static char[][] DIG_CHAR = {{}, {}, {'A', 'B', 'C'}, {'D', 'E', 'F'},
{'G', 'H', 'I'}, {'J', 'K', 'L'}, {'M', 'N', 'O'}, {'P', 'Q', 'R', 'S'},
{'T', 'U', 'V'}, {'W', 'X', 'Y', 'Z'}};
public static void main(String[] args) throws IOException {
String s1 = "telephone.txt";
String s2 = "sample.txt";
Process(s1, s2);
}
public static void Process(String s1, String s2) throws IOException {
int size43 = count(s2, 3);
int size44 = count(s2, 4);
int size47 = count(s2, 7);
/////
System.out.println("lines of 3: "+size43 );
System.out.println("lines of 4: "+size44 );
System.out.println("lines of 7: "+size47 );
/////
String[] WordsOf3 = store(s2, size43, 3);
String[] WordsOf4 = store(s2, size44, 4);
String[] WordsOf7 = store(s2, size47, 7);
/////
System.out.println("lines of 3" );
for(int i = 0; i<size43; i++){
System.out.println( WordsOf3[i] );
}
System.out.println("lines of 4" );
for(int i = 0; i<size44; i++){
System.out.println( WordsOf4[i] );
}
System.out.println("lines of 7" );
for(int i = 0; i<size47; i++){
System.out.println( WordsOf7[i] );
}
/////
String[] s = Char2Dig(WordsOf3);
String[] p = Char2Dig(WordsOf4);
String[] q = Char2Dig(WordsOf7);
Print3(WordsOf3, s, s1);
Print4(WordsOf4, p, s1);
Print7(WordsOf7, q, s1);
}
/** Single method that returns the number of lines of given number of char
* With this single method, no need to write ThreeCharacters, FourCharacters
* and SevenCharacters
*/
public static int count(String fName, int nChar) throws IOException {
Scanner in = new Scanner(new File(fName));
int count = 0;
String tmp; // Note the tmp variable, so that we do not advance twice
while (in.hasNextLine()) {
if (in.nextLine().length() == nChar) {
count++;
}
}
in.close();
return count;
}
/** Single method that returns all the lines of given number of char
* With this single method, no need to write Store3Words, Store4Words
* and Store7Words
*/
public static String[] store(String fName, int size, int nChar) throws IOException {
String[] words = new String[size];
String temp = "";
Scanner in = new Scanner(new File(fName));
int i = 0;
while (in.hasNextLine()) {
temp = in.nextLine();
if (temp.length() == nChar) {
words[i] = temp;
i++;
}
}
in.close();
return words;
}
public static String[] Char2Dig(String[] arr) { // ||
String temp = "";
String q = "";
String str = "";
for (int i = 0; i < arr.length; i++) {
temp = arr[i];
str = "";
for (int j = 0; j < temp.length(); j++) {
for (int m = 2; m < DIG_CHAR.length; m++) {
for (int k = 0; k < DIG_CHAR[m].length; k++) {
if (temp.charAt(j) == DIG_CHAR[m][k]) {
q = q + DIG_CHAR[m];
str = str + q;
break;
}
}
if (q == "") {
continue;
}
break;
}
q = "";
}
arr[i] = str;
}
return arr;
}
public static void Print3(String[] WordsOf3, String[] arr, String s1) throws IOException {
PrintWriter outfile = new PrintWriter(new FileWriter("result.txt"));
Scanner in = new Scanner(new File(s1));
String temp = "";
while (in.hasNextLine()) {
temp = in.nextLine().substring(4, 7);
for (int i = 0; i < arr.length; i++) {
if (arr[i] == temp) {
outfile.println(temp + ": " + WordsOf3[i]);
}
}
}
outfile.close();
}
public static void Print4(String[] WordsOf4, String[] arr, String s1) throws IOException {
PrintWriter outfile = new PrintWriter(new FileWriter("result.txt"));
Scanner in = new Scanner(new File(s1));
String temp = "";
while (in.hasNextLine()) {
temp = in.nextLine().substring(7, 11);
for (int i = 0; i < arr.length; i++) {
if (arr[i] == temp) {
outfile.println(temp + ": " + WordsOf4[i]);
}
}
}
outfile.close();
}
public static void Print7(String[] WordsOf7, String[] arr, String s1) throws IOException {
PrintWriter outfile = new PrintWriter(new FileWriter("result.txt"));
Scanner in = new Scanner(new File(s1));
String temp = "";
while (in.hasNextLine()) {
temp = in.nextLine().substring(4);
for (int i = 0; i < arr.length; i++) {
if (arr[i] == temp) {
outfile.println(temp + ": " + WordsOf7[i]);
}
}
}
outfile.close();
}
}
如果我理解Print3，Print4和Print7背后的逻辑，我会做同样的事情。还要注意我添加了一些print语句来查看发生了什么。这对于查看您的代码是否正在执行它应该执行的操作非常有帮助。