如何为UIPageViewControllerDataSource提供默认实现?

时间:2015-07-27 21:23:26

标签: swift protocols uipageviewcontroller default-implementation

我认为这个问题的答案一般会解决Objective-C协议的问题,但这是我遇到的第一个这类问题。

我希望在实现 UIPageViewControllerDataSourceWithConnections 时使用这些方法。

import UIKit

protocol UIPageViewControllerDataSourceWithConnections: UIPageViewControllerDataSource {
    var connectedViewControllers: [UIViewController] {get}
}

extension UIPageViewControllerDataSourceWithConnections {
    func pageViewController(pageViewController: UIPageViewController,
        viewControllerBeforeViewController viewController: UIViewController
    ) -> UIViewController? {return connectedViewController(
        current: viewController,
        adjustIndex: -
    )}

    func pageViewController(pageViewController: UIPageViewController,
        viewControllerAfterViewController viewController: UIViewController
    ) -> UIViewController? {return connectedViewController(
        current: viewController,
        adjustIndex: +
    )}

    private func connectedViewController(
        current viewController: UIViewController,
        adjustIndex: (Int, Int) -> Int
    ) -> UIViewController? {
        let requestedIndex = adjustIndex(connectedViewControllers.indexOf(viewController)!, 1)
        return connectedViewControllers.indices.contains(requestedIndex) ?
            connectedViewControllers[requestedIndex] : nil
    }

    func presentationCountForPageViewController(pageViewController: UIPageViewController)
    -> Int {return connectedViewControllers.count}

    func presentationIndexForPageViewController(pageViewController: UIPageViewController)
    -> Int {
        return connectedViewControllers.indexOf(pageViewController.viewControllers!.first!)!
    }
}

然而,这不会编译。我必须实现这个废话以使事情有效。你能告诉我为什么吗?是否有更轻松的解决方案?

// connectedViewControllers is defined elsewhere in InstructionsPageViewController.
extension InstructionsPageViewController: UIPageViewControllerDataSourceWithConnections {

    // (self as UIPageViewControllerDataSourceWithConnections) doesn't work.
    // Workaround: use a different method name in the protocol

    func pageViewController(pageViewController: UIPageViewController,
        viewControllerBeforeViewController viewController: UIViewController
    ) -> UIViewController? {
        return pageViewController(pageViewController,
            viewControllerBeforeViewController: viewController
        )
    }

    func pageViewController(pageViewController: UIPageViewController,
        viewControllerAfterViewController viewController: UIViewController
    ) -> UIViewController? {
        return pageViewController(pageViewController,
            viewControllerAfterViewController: viewController
        )
    }


    // (self as UIPageViewControllerDataSourceWithConnections)
    // works for the optional methods.

    func presentationCountForPageViewController(pageViewController: UIPageViewController)
    -> Int {
        return (self as UIPageViewControllerDataSourceWithConnections)
            .presentationCountForPageViewController(pageViewController)
    }

    func presentationIndexForPageViewController(pageViewController: UIPageViewController)
    -> Int {
        return (self as UIPageViewControllerDataSourceWithConnections)
            .presentationIndexForPageViewController(pageViewController)
    }
}

1 个答案:

答案 0 :(得分:5)

当你遇到这样的问题时,你想知道Swift语言本身的局限性,它有助于将其简化为更简单的问题版本。

首先,让我们问:是否有可能扩展采用协议的协议,作为将该协议的要求的默认实现注入最终采用类的方法?是的;这段代码是合法的:

protocol Speaker {
    func speak()
}
protocol DefaultSpeaker : Speaker {
}
extension DefaultSpeaker {
    func speak() {
        print("howdy")
    }
}
class Adopter : DefaultSpeaker {

}

好的,那你的代码还有什么用呢?好吧,它还注入了额外的要求(实例变量)。这合法吗?是的。这段代码也是合法的:

protocol Speaker {
    func speak()
}
protocol DefaultSpeaker : Speaker {
    var whatToSay : String {get}
}
extension DefaultSpeaker {
    func speak() {
        print(self.whatToSay)
    }
}
class Adopter : DefaultSpeaker {
    var whatToSay = "howdy"
}

那么Swift不喜欢什么?我们在这里做了什么,你的代码呢?事实是原始协议是@objc。如果我们将protocol Speaker更改为@objc protocol Speaker(并进行所有其他必要的更改),代码将停止编译:

@objc protocol Speaker {
    func speak()
}
@objc protocol DefaultSpeaker : Speaker {
    var whatToSay : String {get}
}
extension DefaultSpeaker {
    func speak() {
        print(self.whatToSay)
    }
}
class Adopter : NSObject, DefaultSpeaker { // ERROR
    var whatToSay = "howdy"
}

我猜这是因为Objective-C对协议扩展一无所知。由于我们所需的协议方法的实现取决于协议扩展,因此我们不能以满足编译器的方式采用协议,即从Objective-C的角度满足要求。我们必须在课堂上实现这些要求,其中Objective-C可以看到我们的实现(这正是您的解决方案所做的):

@objc protocol Speaker {
    func speak()
}
@objc protocol DefaultSpeaker : Speaker {
    var whatToSay : String {get}
}
extension DefaultSpeaker {
    func speak2() {
        print(self.whatToSay)
    }
}
class Adopter : NSObject, DefaultSpeaker {
    var whatToSay = "howdy"
    func speak() {
        self.speak2()
    }
}

所以,我得出结论,你的解决方案是最好的。

你正在做的事实上更像是这样,我们在采用者类上使用扩展来注入“钩子”方法:

@objc protocol Speaker {
    func speak()
}
@objc protocol DefaultSpeaker : Speaker {
    var whatToSay : String {get}
}
extension DefaultSpeaker {
    func speak2() {
        print(self.whatToSay)
    }
}
class Adopter : NSObject {
}
extension Adopter : DefaultSpeaker {
    var whatToSay : String { return "howdy" }
    func speak() {
        self.speak2()
    }
}

这是有效的,因为最后extension是Objective-C 可以看到的东西:Objective-C类的扩展实际上是Objective-C理解的类别。