我最近编写了一个简单的Java服务器和一个客户端来测试服务器。服务器应该从客户端接收消息,并发回消息的随机子串。问题是:当我使用客户端程序发送消息时,服务器不响应。然后,当我终止客户端程序时,服务器跳跃到行动,并尝试将数据发送回客户端。服务器正确读取数据,但只有在我停止客户端程序时才开始处理它。
这是客户端代码:
import java.io.*;
import java.net.*;
class ServerTest{
public static void main(String args[]) throws Exception{
Socket clientSocket = new Socket(myIpAdress, 8001);
//Send the message to the server
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(clientSocket.getOutputStream()));
String sendMessage = "randSubstring:StackOverflowIsAwsome";
bw.write(sendMessage);
bw.flush();
System.out.println("Message sent: "+sendMessage);
String message = new BufferedReader(new InputStreamReader(clientSocket.getInputStream())).readLine();
System.out.println("Message received from the server : " +message);
clientSocket.close();
}
}
我的服务器代码包含两个类。这个是听众:
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.ServerSocket;
import java.net.Socket;
public class ServerListener {
public static void main(String args[]) throws Exception {
String clientSentence;
ServerSocket socket = new ServerSocket(8001);
while(true) {
Socket connectionSocket = socket.accept();
BufferedReader input = new BufferedReader(new InputStreamReader(connectionSocket.getInputStream()));
//DataOutputStream output = new DataOutputStream(connectionSocket.getOutputStream());
clientSentence = input.readLine();
if(clientSentence.startsWith("randSubstring:")){
Thread connection = new Thread(new ServerConnection(connectionSocket, clientSentence));
connection.start();
}
Thread.sleep(300);
}
}
}
这是在客户端停止之前不会启动的线程:
import java.io.BufferedOutputStream;
import java.io.BufferedWriter;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.net.Socket;
import java.util.Random;
public class ServerConnection implements Runnable{
private Socket serverConnection;
private String sentence;
public ServerConnection(Socket connection, String clientSentence){
serverConnection = connection;
sentence = clientSentence;
}
@Override
public void run() {
Random r = new Random();
String substring = sentence.substring(0, r.nextInt(sentence.length()));
try {
OutputStream os = serverConnection.getOutputStream();
OutputStream out = new BufferedOutputStream(os);
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(out));
bw.write(substring);
bw.close();
out.close();
os.close();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
我正在使用带优胜美地的Macintosh。这是因为我试图在同一台计算机上运行程序,或者如果程序是从不同的计算机运行会出现问题吗?任何帮助表示赞赏。
答案 0 :(得分:0)
在服务器中,你执行readLine(..),这意味着它将等待行尾字符。
但是在您的发件人代码中,您只需发送一个没有行结尾的字符串。
因此,要么你确保你也发送了行尾char或你的服务器等待其他东西作为" delimiter"
答案 1 :(得分:0)
你正在读一条线,但你不是在写一条线。在发送的消息中添加行终止符。否则readLine()
将不会返回,直到对等方关闭连接。
NB接受后try
块中的I / O应该在Runnable中,而不是在Runnable中。不要在接受循环中执行I / O.