Question

如何删除重复项并合并帐户类型？

我有一个根据帐户类型报告重复电话的通话记录。

例如：

Telephone       | Account Type

304-555-6666    | R

304-555-6666    | C

我知道如何使用RANK \ MAXCOUNT
但在删除重复项之前，我需要将帐户类型重置为“B”，重复项有多种帐户类型。

在示例中，幸存的副本将是：

Telephone       | Account Type

304-555-6666    | B

警告，不保证重复的手机有多种帐户类型。

示例：

Telephone       | Account Type

999-888-6666    | R

999-888-6666    | R

因此，幸存的副本应该是：

Telephone       | Account Type

999-888-6666    | R

如何删除重复项并同时重置帐户类型？

--
-- Remove Duplicate Recordings
--
SELECT * FROM (
SELECT  i.dateofcall ,
      i.recordingfile ,
        i.telephone ,        
        s.accounttype ,
        ROW_NUMBER() OVER (PARTITION BY i.telephone ORDER BY i.dateofcall DESC) AS 'RANK' ,
                    COUNT(i.telephone) OVER (PARTITION BY  i.telephone) AS 'MAXCOUNT'
FROM    #myactions i
        LEFT JOIN #myphone s ON s.interactionID = i.Interactionid 
) x
WHERE [RANK] = [MAXCOUNT]

Answer 1

试试这个？

select
    x.dateofcall
    , x.recordingfile
    , x.telephone
    , case when count(*) > 2 then 'B' else max(x.accounttype) end accounttype
    (
    select
        i.dateofcall
        , i.recordingfile
        , i.telephone
        , s.accounttype
    from
        #myactions i
        LEFT JOIN #myphone s ON s.interactionID = i.Interactionid
    group by
        i.dateofcall
        , i.recordingfile
        , i.telephone
        , s.accounttype
    ) x
group by
    x.dateofcall
    , x.recordingfile
    , x.telephone

Answer 2

基本上，您需要将业务检查放在外部的案例陈述中。

编辑：我还添加了B，R和C的逻辑。还做了一个sql小提琴 - 小提琴 - http://sqlfiddle.com/#!6/b5ef5/7

SELECT 
    x.dateofcall,
    x.recordingfile,
    x.telephone,
    COALESCE(
        CASE WHEN x.maxcount>1 AND value>x.maxcount AND value<(2*x.maxcount) THEN 'B' ELSE NULL END,
        CASE WHEN x.maxcount>1 AND value= (2*x.maxcount) THEN 'C' ELSE NULL END,
        CASE WHEN x.maxcount>1 AND value= x.maxcount THEN 'R' ELSE NULL END,
        x.accounttype ) as accounttype, 
    x.rank,
    x.maxcount
FROM (
    SELECT  i.dateofcall ,
            i.recordingfile ,
            i.telephone ,        
            s.accounttype ,
            ROW_NUMBER() OVER (PARTITION BY i.telephone ORDER BY i.dateofcall DESC) AS 'RANK' ,
            COUNT(i.telephone) OVER (PARTITION BY  i.telephone) AS 'MAXCOUNT',
            SUM(CASE WHEN s.accounttype LIKE 'R' THEN 1 ELSE 2 END) OVER (PARTITION BY  i.telephone) as Value
    FROM 
        myactions i LEFT JOIN myphone s 
        ON s.interactionID = i.Interactionid 
    ) x
WHERE [RANK] = [MAXCOUNT]

Answer 3

SELECT * FROM (
SELECT  i.dateofcall ,
      i.recordingfile ,
        i.telephone ,        
        s.accounttype ,
        ROW_NUMBER() OVER (PARTITION BY i.telephone ORDER BY i.dateofcall DESC) AS 'RANK' ,
        COUNT(i.telephone) OVER (PARTITION BY  i.telephone) AS 'MAXCOUNT',
        DENSE_RANK() OVER ( PARTITION BY i.telephone ORDER BY s.accounttype DESC ) AS 'ContPhone'
FROM    #myactions i
        LEFT JOIN #myphone s ON s.interactionID = i.Interactionid 
) x
WHERE [RANK] = [MAXCOUNT]

合并值时删除重复项

3 个答案: