我试图循环我创建的功能。它目前只运行一次然后停止。在当前状态下,我使用setTimeout
来延迟功能。
使用Javascript:
function firstSlide() {
setTimeout(function() {
$('.survey').addClass('slide');
}, 400);
setTimeout(function() {
$('.curve-1, .curve-2').addClass('slide');
}, 1400);
}
function secondSlide() {
$('.cover-1').fadeOut(400, function() {
$('.survey, .curve-1, .curve-2').removeClass('slide');
$('.cover-2').fadeIn(400);
setTimeout(function() {
$('.curve-3, .curve-4').addClass('slide');
}, 400);
setTimeout(function() {
$('.magnify-1').addClass('pop');
}, 1400);
setTimeout(function() {
$('.magnify-2').addClass('pop');
}, 2400);
});
}
function thirdSlide() {
$('.cover-2').fadeOut(400, function() {
$('.curve-3, .curve-4').removeClass('slide');
$('.magnify-1, .magnify-2').removeClass('pop');
$('.cover-3').fadeIn(400);
setTimeout(function() {
$('.double-survey').addClass('slide');
}, 400);
});
}
setTimeout(firstSlide, 0);
setTimeout(secondSlide, 6000);
setTimeout(thirdSlide, 12000);
HTML
<div class="cover-1 cover">
<img class="curve-1" src="images/home/curve-1@2x.png">
<img class="curve-2" src="images/home/curve-2@2x.png">
<img class="survey" src="images/home/survey@2x.png">
</div>
<div class="cover-2 cover" style="display: none">
<img class="curve-3" src="images/home/curve-3@2x.png">
<img class="curve-4" src="images/home/curve-4@2x.png">
<img class="magnify-1" src="images/home/magnify-1@2x.png">
<img class="magnify-2" src="images/home/magnify-2@2x.png">
</div>
<div class="cover-3 cover" style="display: none">
<img class="curve-1" src="images/home/curve-1@2x.png">
<img class="curve-2" src="images/home/curve-2@2x.png">
<img class="double-survey" src="images/home/double-survey@2x.png">
</div>
答案 0 :(得分:0)
在每个函数结束时调用下一个函数
function firstSlide(){
............
setTimeout(secondSlide, 6000);
}
function secondSlide() {
..........
setTimeout(thirdSlide, 12000);
}
function thirdSlide() {
................
setTimeout(firstSlide, 0);
}
并删除这两个:
setTimeout(secondSlide, 6000);
setTimeout(thirdSlide, 12000);