Question

这是我使用的代码：

 admin_no   rank    total_score Descending 1    
08/00076    1   1615
10/00170    2   1613
12/00300    3   1609
09/00091    4   1604
10/00182    5   1600
09/00159    6   1583
10/00177    7   1574
09/00152    8   1561
09/00165    9   1540
10/00176    10  1516
13/00354    11  1497
10/00178    12  1470
14/00348    13  1409
14/00346    14  12
15/00371    15  12
09/00156    16  7

这是Output ::

Admin       Rank Scores
14/00348    13  1409
14/00346    14  12
15/00371    14  12
09/00156    16  7

这里的问题是，学生14/00346和15/00371分别得到12分，他们分别排名第14和第15，而2015年9月，7分排名第16。我想要的是 .......................

{{1}}

请帮帮我

Answer 1

SET @total_score = 0;

SELECT admin_no, CASE WHEN @total_score = total_score THEN rank - 1 ELSE rank END rank, @total_score := total_score total_score FROM 
(
    SELECT admin_no,rank,total_score
    FROM (SELECT *,  @auto:=@auto+1 AS rank 
    FROM (SELECT * FROM 
      (SELECT admin_no, SUM(exam)+SUM(ca) AS total_score,year,class_s
        FROM subjects_1 ,
        (SELECT @auto:=0, @marks:=0) as init WHERE `class_s`='Grade 2' and `year`='2014/2015'
         GROUP BY admin_no ) sub ORDER BY total_score DESC)t) t2
) result

Php to Rank如果他们在total_scores中有关系，则连续得分

1 个答案: