Question

我正在创建一个论坛，现在我正在试图弄清楚如何计算某个主题中的回复数量。我想要计算每个topic_id＃的行数。因此，如果主题ID为5且我的topic_id＃5数据库中有10行，我希望它计数并输出10。

我尝试像这样构建我的查询

 $query2 = mysqli_query($con,"SELECT t.*, COUNT(p.topic_id) AS tid2 FROM forum_topics AS t, forum_posts AS p ORDER BY topic_reply_date DESC")

然而，所有这一切都搞砸了我的原始查询，这就是......

$query2 = mysqli_query($con,"SELECT * FROM forum_topics WHERE `category_id` ='".$cid."' ORDER BY topic_reply_date DESC")

它现在只显示1个主题，而不是我拥有的15个主题，它输出的数量非常大，为406个。

如何才能获得以下代码，仅计算与正在输出的主题相关的topic_id，并仍允许输出我的所有主题？

$query2 = mysqli_query($con,"SELECT t.*, COUNT(p.topic_id) AS tid2 FROM forum_topics AS t, forum_posts AS p ORDER BY topic_reply_date DESC")
or die ("Query2 failed: %s\n".($query2->error));
$numrows2 = mysqli_num_rows($query2);
//if ( false===$query2 ) {
    // die(' Query2 failed: ' . htmlspecialchars($query2->error));
//}
if($numrows2 > 0){
    $topics .= "<table width='100%' style='border-collapse: collapse;'>";
    //Change link once discussion page is made
    $topics .= "<tr><td colspan='3'><a href='discussions.php'>Return to Discussion Index</a>".$logged."<hr /></td></tr>";
    $topics .= "<tr style='background-color: #dddddd;'><td>Topic Title</td><td width='65' align='center'>Replies</td><td width='65' 
    align='center'>Views</td></tr>";
    $topics .= "<tr><td colspan='3'><hr /></td></tr>";
    while($row = mysqli_fetch_assoc($query2)){
        $tid = $row['id'];
        $title = $row['topic_title'];
        $views = $row['topic_views'];
        $replies = $row['tid2'];
        $date = $row['topic_date'];
        $creator = $row['topic_creator'];
        $topics .= "<tr><td><a href='forum_view_topic.php?cid=".$cid."&tid=".$tid."'>".$title."</a><br /><span class='post_info'>Posted 
        by: ".$creator." on ".$date."</span></td><td align='cener'>".$replies."</td><td align='center'>".$views."</td></tr>";
        $topics .= "<tr><td colspan='3'><hr /></td></tr>";
    }

Answer 1

使用GROUP BY子句（tutorial）：

SELECT t.*, COUNT(p.topic_id) AS tid2 
FROM forum_topics AS t JOIN forum_posts AS p on t.id = p.topic_id 
GROUP BY t.id

另请注意，我的示例中使用了OUTER JOIN（而不是示例中的CROSS JOIN）。

COUNT个与id相关联的数据库行

1 个答案: