PHP MySQL从投递箱选择中插入多个值

Question

我有一个由MySQL表填充的表，我试图将表中的选定行插入到另一个表中。

表格如下所示： 。

表中前三个字段来自另外两个表，具体取决于字段值。

下拉选项由用户使用：

提供

$sql = "SELECT project_proposals.id, project_proposals.title, project_proposals.description, project_proposals.academicname, flux_student_records.studentname, flux_student_records.id, flux_student_records.programme, flux_student_records.academicdiscipline FROM project_proposals JOIN flux_student_records ON project_proposals.academicdiscipline = flux_student_records.academicdiscipline 
WHERE project_proposals.academicdiscipline = '$academicdiscipline' AND flux_student_records.studentname = '$studentname'";

$retval = mysql_query($sql) or die(mysql_error());

将这些多个选定行插入另一个表的最佳方法是什么？谢谢。

Answer 1

＆＃34;选择进入＆＃34;是要走的路。

    SELECT into YourNewTable select project_proposals.id, project_proposals.title, project_proposals.description, project_proposals.academicname, flux_student_records.studentname, flux_student_records.id, flux_student_records.programme, flux_student_records.academicdiscipline FROM project_proposals JOIN flux_student_records ON project_proposals.academicdiscipline = flux_student_records.academicdiscipline 
WHERE project_proposals.academicdiscipline = '$academicdiscipline' AND flux_student_records.studentname = '$studentname'";

希望你觉得这很有用。

Answer 2

您可以循环播放帖子，然后使用该信息执行某些操作。 例如：

    <?php

function readDataForwards($dbh) {
  $sql = 'SELECT * FROM yourdb';
  try {
    $stmt = $dbh->prepare($sql, array(PDO::ATTR_CURSOR => PDO::CURSOR_SCROLL));
    $stmt->execute();
    while ($row = $stmt->fetch(PDO::FETCH_NUM, PDO::FETCH_ORI_NEXT)) {
      $data = $row[0] . "\t" . $row[1] . "\t" . $row[2] . "\n";
      print $data;
      #insert the data into another database
      #you can also filter some duplicated items that you already 
      #have in the database
    }
    $stmt = null;
  }
  catch (PDOException $e) {
    print $e->getMessage();
  }
}

    ?>

这将输出：数据库中的行 但它也可以将行插入数据库。