1064 - 您的SQL语法出错;

Question

收到错误：

1064 - 您的SQL语法出错;

 check the manual that corresponds to your MySQL 
 server version for the right syntax to use near 
 't1.pard_suma LIMIT 0, 25' at line 5

NO DISTINCT error:
#1054 - Unknown column 't1.pard_suma' in 'having clause' 

SELECT t1.invoice_nr
FROM irasai t1
LEFT JOIN apmokejimai t2 ON t1.invoice_nr = t2.invoice_nr
GROUP BY t1.id
HAVING SUM(DISTINCT t2.suma) <> t1.pard_suma

但列存在！

如何解决这个问题？

这就像我需要的那样，但我希望得到所有的invoice_nr，其中pard_suma高于所有apmokejimai.suma（将它们全部用相同的invoice_nr汇总）以及invoice_nr不存在于apkomejimai表中

感谢。

Answer 1

HAVING子句在<>比较运算符的右侧寻找静态值。所以你必须做这样的事情：

SELECT t1.*
FROM irasai t1
LEFT JOIN apmokejimai t2 ON t1.invoice_nr = t2.invoice_nr
GROUP BY t1.id
HAVING SUM(DISTINCT t2.suma) <> (
  SELECT MAX(pard_suma) 
  FROM irasai 
  WHERE invoice_nr = t1.invoice_nr 
  GROUP BY invoice_nr
)

示例：http://sqlfiddle.com/#!9/90760/6

create table irasai (
  id int,
  invoice_nr int,
  pard_suma int
);

create table apmokejimai (
  invoice_nr int,
  suma int
);

insert into irasai values (1, 1, 100);
insert into apmokejimai values (1, 20), (1, 40), (1, 40);

insert into irasai values (1, 1, 200);
insert into apmokejimai values (1, 40), (1, 80), (1, 81);

请注意，我故意在apmokejimai中输入的数据总数不超过200。

在<>的SQL右侧，我创建了一个子查询，用于计算HAVING可以与之比较的数字。我猜这有点类似于你想要做的事情。

**在评论中回答OP的问题*

create table irasai (
  id int,
  invoice_nr int,
  pard_suma int
);

create table apmokejimai (
  invoice_nr int,
  suma int
);

insert into irasai values (1, 1, 100);
insert into apmokejimai values (1, 20), (1, 40), (1, 40);

insert into irasai values (2, 2, 200);
insert into apmokejimai values (2, 40), (2, 80), (2, 81);

insert into irasai values (3, 3, 300);

select
  t1.invoice_nr,
  max(t1.pard_suma) as pardtotal,
  sum(t2.suma) as sumatotal
from irasai t1
left join apmokejimai t2 on t1.invoice_nr = t2.invoice_nr
group by invoice_nr
having pardtotal <> sumatotal or sumatotal is null

示例：http://sqlfiddle.com/#!9/fb331/3

Mysql选择值不相等的地方

1064 - 您的SQL语法出错;

1 个答案: