Question

我能够在特定日期之前三年和之后三年对项目进行分组，但我无法在三年内打破项目计数。你能好好看一下吗？

SELECT
ITEM,
CASE WHEN DATE >='12/6/02' AND DATE <'12/6/05' AND ITEM ='RICE' THEN 'RICE PRIOR'
CASE WHEN DATE >='12/06/05' AND DATE <'12/6/08' AND ITEM ='RICE' THEN 'RICE POST'
END AS TYPE,
COUNT (QTY) AS RICE
FROM #TEMP

WHERE DATE >='12/6/02'
AND DATE <'12/6/08'
GROUP BY ITEM,
 CASE WHEN DATE >='12/6/02' AND DATE <'12/6/05' AND ITEM ='RICE' THEN 'RICE PRIOR'
CASE WHEN DATE >='12/06/05' AND DATE <'12/6/08' AND ITEM ='RICE' THEN 'RICE POST'
END

有人可以看一下，把它分解成三年吗？

运行此脚本，我的结果显示

Type,     Rice
Rice Prior 444
Rice Post  555

我的愿望输出将是：

Year3, Year2, Year1  Year1, Year2, Year3
4      44     400     5      500    50

谢谢，乔

Answer 1

这应该使用pivot和date参数匹配您想要的查询，因此您不必在所有日期和条件下对其进行硬编码。

DATEADD

上述方法并未考虑闰年。您可以应用@ JPW的方法来使用知道闰年的DECLARE @D DATE = '12/6/2005' SELECT ITEM, [-3] AS Year3, [-2] AS Year2, [-1] AS Year1, [1] AS Year1, [2] AS Year2, [3] AS Year3 FROM ( SELECT ITEM, CASE WHEN DATE BETWEEN DATEADD(YEAR, -3, @D) AND DATEADD(YEAR, -2, @D) THEN -3 WHEN DATE BETWEEN DATEADD(YEAR, -2, @D) AND DATEADD(YEAR, -1, @D) THEN -2 WHEN DATE BETWEEN DATEADD(YEAR, -1, @D) AND DATEADD(YEAR, -0, @D) THEN -1 WHEN DATE BETWEEN DATEADD(YEAR, +0, @D) AND DATEADD(YEAR, +1, @D) THEN 1 WHEN DATE BETWEEN DATEADD(YEAR, +1, @D) AND DATEADD(YEAR, +2, @D) THEN 2 WHEN DATE BETWEEN DATEADD(YEAR, +2, @D) AND DATEADD(YEAR, +3, @D) THEN 3 ELSE NULL END AS [YR], QTY FROM #TEMP ) T PIVOT (MAX(QTY) FOR [YR] IN ([-3], [-2], [-1], [1], [2], [3])) PVT。您只需要了解每个地区的第一天和最后一天的边界情景。在这种方法中，第一场比赛获胜，所以今天的日期将是年份＆＃34; -1＆＃34;。

{{1}}

Answer 2

根据您的示例输出，我认为下面的查询可能就是您想要的。您可能需要调整日期范围以满足您的需求，但一般的想法应该是明确的：

DECLARE @d date = '2005-07-27';
WITH cte AS 
(
    SELECT
       ITEM
       , SUM(CASE WHEN DATE BETWEEN DATEADD(YEAR, -3, @D) AND DATEADD(YEAR, -2, @D) AND ITEM ='RICE' THEN QTY END) 'RICE PRIOR -3'
       , SUM(CASE WHEN DATE BETWEEN DATEADD(YEAR, -2, @D) AND DATEADD(YEAR, -1, @D) AND ITEM ='RICE' THEN QTY END) 'RICE PRIOR -2'
       , SUM(CASE WHEN DATE BETWEEN DATEADD(YEAR, -1, @D) AND DATEADD(YEAR, -0, @D) AND ITEM ='RICE' THEN QTY END) 'RICE PRIOR -1'
       , SUM(CASE WHEN DATE BETWEEN DATEADD(YEAR, +0, @D) AND DATEADD(YEAR, +1, @D) AND ITEM ='RICE' THEN QTY END) 'RICE POST +1'
       , SUM(CASE WHEN DATE BETWEEN DATEADD(YEAR, +1, @D) AND DATEADD(YEAR, +2, @D) AND ITEM ='RICE' THEN QTY END) 'RICE POST +2'
       , SUM(CASE WHEN DATE BETWEEN DATEADD(YEAR, +2, @D) AND DATEADD(YEAR, +3, @D) AND ITEM ='RICE' THEN QTY END) 'RICE POST +3'
    FROM #TEMP
    WHERE DATE >='2002-05-12' AND DATE <'2008-06-12'
    GROUP BY ITEM
)

SELECT * FROM CTE;

Answer 3

所以基本上你可以在PIVOT的选择部分中应用你的计数逻辑，然后在几年内转动结果集

SELECT ITEM, [2002] AS[Year-3],[2003] AS [Year-2], [2004] AS [Year-1],
[2005] AS [Year1],[2006] AS [Year2],[2007] AS [Year3]
FROM (
-- Your logic here
SELECT
ITEM,
YEAR(Date) as Y,
COUNT (quantity) AS RICE
FROM [dbo].[temp]
WHERE DATE >='12/6/01'
AND DATE <'12/6/08'
GROUP BY ITEM,YEAR(Date)
) as s
PIVOT
(
    SUM(RICE)
    FOR Y IN ([2002], [2003], [2004], [2005],[2006],[2007])
)AS p

Sql小提琴链接 http://sqlfiddle.com/#!6/fa406/2

如何在SQL中显示年份

3 个答案: