Question

我想使用GET函数从表中检索信息。但它不起作用。拜托，我做错了什么？

＆＃13;

  <td><?php echo $row['count(*)']; ?></td>
        <td>N<?php echo number_format($row['sum(basic)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(hmo)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(dha)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(tax)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(netpay)'],2); ?></td>
        <td><a href="view_payroll_month.php?month=<?php echo $row['year(date)'];?>"><?php echo $row['year(date)'];?></a> </td>
     	</tr><?php }?>

＆＃13;

第二页我希望结果显示在

中

＆＃13;

$year = $_GET['year'];


$qry = "SELECT count(*), sum(basic), sum(hmo), sum(pension), sum(dha), sum(tax), sum(netpay), month(date) FROM salary WHERE year(date) ='$year' GROUP BY month(date)";
$run = mysql_query($qry) or die(mysql_error());


<?php while ($row = mysql_fetch_array($run)) {?>

 
  <tr>
        <td><?php echo $row['count(*)']; ?></td>
        <td>N<?php echo number_format($row['sum(basic)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(hmo)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(dha)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(tax)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(netpay)'],2); ?></td>
        <td><a href="view_month.php?month=<?php echo $row['month(date)'];?>"><?php echo $row['month(date)'];?></a> </td>
     	</tr><?php }?>

＆＃13;

Answer 1

这样可行。

<td><?php echo $row['count(*)']; ?></td>
        <td>N<?php echo number_format($row['sum(basic)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(hmo)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(dha)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(tax)'],2); ?></td>
        <td>N<?php echo number_format($row['sum(netpay)'],2); ?></td>
        <td><a href="view_payroll_month.php?year=<?php echo $row['year(date)'];?>">><?php echo $row['year(date)'];?></a> </td>
        </tr><?php }?>

原因：您曾尝试在href内传递值。并尝试从获取年份参数检索。只需在href内每月更改一次。你现在可以找回一年了。 name参数必须等于获取name参数。

Answer 2

这是您链接中的网址：

view_payroll_month.php?month=...

查询字符串参数名为month。但是您尝试获取名为year的值：

$_GET['year']

查询字符串和/或表单值是键/值对。这些值由与它们关联的键（名称）唯一标识。所以你需要：

按month而不是year或
传递值year而不是month或
除了year之外，还传递值month。

这样的事情：

<a href="view_payroll_month.php?month=<?php echo $row['month(date)']; ?>&year=<?php echo $row['year(date)']; ?>">

用get来检索php中的值

2 个答案: