Question

我想使用从一个活动到另一个活动的共享首选项的值，例如，如果我的pin_activity的引脚设置为on，则应禁用来自另一个活动的模式，并显示＆＃34; PinService为ON的Toast ，你不能开启PatternService＆＃34;反之亦然。我没有得到如何使用共享偏好值。请帮我解决这个问题

这是我的两个活动的代码。

pin_activity.java

    s2 = (Switch) findViewById(R.id.switch2);


    spref = PreferenceManager.getDefaultSharedPreferences(getApplicationContext());
    s2.setChecked(spref.getBoolean("SwitchButton", false));


    s2.setOnClickListener(new ToggleButton.OnClickListener() {

        public void onClick(View v) {

            SharedPreferences.Editor editor = spref.edit();
            editor.putBoolean("SwitchButton", s2.isChecked());
            // editor.putString("switch_state", "value");
            //switch_state=editor.putBoolean("SwitchButton", s2.isChecked());
            editor.commit();
            //  Toast.makeText(getApplicationContext(), "Switch is ON", Toast.LENGTH_SHORT).show();
        }
    });

Pattern_activity.java

   SharedPreferences sharedPreferences = PreferenceManager
           .getDefaultSharedPreferences(getApplicationContext());
    s1.setChecked(sharedPreferences.getBoolean("toggleButton", false));
    switch1= sharedPreferences.getBoolean("editor",s1.isChecked() );
    if (switch1== true)
    {
        s1.setEnabled(false);
        Toast.makeText(getApplicationContext(), "PinService is ON, You can't Make PatternService ON", Toast.LENGTH_SHORT).show();
    }
    else
    {
        s1.setEnabled(true);
    }



    s1.setOnClickListener(new ToggleButton.OnClickListener() {

        public void onClick(View v) {
            SharedPreferences sharedPreferences = PreferenceManager
                    .getDefaultSharedPreferences(getApplicationContext());
            SharedPreferences.Editor editor = sharedPreferences.edit();

            //switch1= sharedPreferences.getString("switch_state", null);
            editor.commit();
            //  Toast.makeText(getApplicationContext(), "Switch is ON", Toast.LENGTH_SHORT).show();
        }
    });

Answer 1

您需要使用相同的密钥进行设置。

在您的示例中，您使用“SwitchButton”来读取/写入pin_activity中的开关状态，使用“editor”来读取（假设）相同的值。哪个不行。

因此，将关键字符串提取为常量，如public static String PIN_STATE = "PIN_STATE";。

in pin_activity：

s2 = (Switch) findViewById(R.id.switch2);


    spref = PreferenceManager.getDefaultSharedPreferences(getApplicationContext());
    s2.setChecked(spref.getBoolean(PIN_STATE, false));


    s2.setOnClickListener(new ToggleButton.OnClickListener() {

        public void onClick(View v) {

            SharedPreferences.Editor editor = spref.edit();
            editor.putBoolean(PIN_STATE, s2.isChecked());
            // editor.putString("switch_state", "value");
            //switch_state=editor.putBoolean(PIN_STATE, s2.isChecked());
            editor.commit();
            //  Toast.makeText(getApplicationContext(), "Switch is ON", Toast.LENGTH_SHORT).show();
        }
    });

在Pattern_activity中

：

SharedPreferences sharedPreferences = PreferenceManager
           .getDefaultSharedPreferences(getApplicationContext());
    s1.setChecked(sharedPreferences.getBoolean("toggleButton", false));
    switch1= sharedPreferences.getBoolean(PIN_STATE, s1.isChecked() );
    if (switch1== true)
    {
        s1.setEnabled(false);
        Toast.makeText(getApplicationContext(), "PinService is ON, You can't Make PatternService ON", Toast.LENGTH_SHORT).show();
    }
    else
    {
        s1.setEnabled(true);
    }

从那以后你可能需要为PATTERN_STATE执行类似的操作，并且通常会理顺你的按钮状态，因为它们看起来有点混乱。

共享首选项值

1 个答案: