Question

<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "dhandhar";
$conn = new mysqli($servername, $username, $password, $dbname);

?>
<?php
$id=$_GET['id'];

$name=$_POST['name']; 
$fathers_name=$_POST['fathers_name'];
$gotra=$_POST['gotra'];
$image=$_POST['image'];
$village=$_POST['village'];
$company_name=$_POST['company_name'];
$address1=$_POST['address1'];
$address2=$_POST['address2'];
$city=$_POST['city'];
$pincode=$_POST['pincode'];
$mobile1=$_POST['mobile1'];
$mobile2=$_POST['mobile2'];
$village_number=$_POST['village_number'];

if($_POST['edit2'])
{
$sql = "UPDATE members_data SET name='$name', fathers_name='$fathers_name', gotra='$gotra', image='$image', village=$village', company_name='$company_name', address1='$address1', address2='$address2', city='$city', pincode='$pincode', mobile1='$mobile1', mobile2='$mobile2', village_number='$village_number' )VALUES('$name', '$fathers_name', '$gotra', '$image', '$village', '$company_name', '$address1', '$address2', '$city', '$pincode', '$mobile1', '$mobile2', '$village_number' WHERE id= '".$id."'";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}


$sql = "DELETE FROM edit_members_data WHERE id= '".$id."'";

if ($conn->query($sql) === TRUE) {
echo "Record deleted successfully";
} else {
echo "Error deleting record: " . $conn->error;
$conn->close();
}
}
?>
<script type="text/javascript">window.location="admin_approve.php"</script>

我收到以下错误：

错误：UPDATE members_data SET name =＆＃39;名称测试＆＃39;，fathers_name =＆＃39;测试姓名＆＃39;，gotra =＆＃39; NA＆＃39;，image =＆＃39; award3.jpg＆＃39;，village = NA＆＃39;， company_name =＆＃39; test_company＆＃39;，address1 =＆＃39;测试地址＆＃39;，地址2 =＆＃39;＆＃39;， city =＆＃39; test City＆＃39;，pincode =＆＃39; test pincode＆＃39;，mobile1 =＆＃39; 000＆＃39;， mobile2 =＆＃39; 000＆＃39;，village_number =＆＃39;＆＃39; ）VALUES（＆＃39;名称测试＆＃39;，＆＃39;测试名称＆＃39;，＆＃39; NA＆＃39;，＆＃39; award3.jpg＆＃39;，＆＃39; NA＆＃39;，＆＃39; test_company＆＃39;，＆＃39;测试地址＆＃39;，＆＃ 39;＆＃39;，＆＃39;测试城市＆＃39;，＆＃39;测试密码＆＃39;，＆＃39; 000＆＃39;，＆＃39; 000＆＃39;，＆＃39;＆＃39;在哪里id =＆＃39; 2＆＃39; 您的SQL语法有错误;检查与MySQL服务器版本对应的手册，以获得正确的语法在＆＃39;＆＃39;，company_name =＆＃39; test_company＆＃39;，地址1 =＆＃39;测试地址＆＃39;， address2 =＆＃39;＆＃39;，city =＆＃39; test＆＃39;在第1行记录删除成功

Answer 1

缺少一条报价：village=$village'必须为village='$village'

此外，您应该使用预准备语句来阻止sql注入，并使查询更具可读性。

Answer 2

请更新您的代码

WHERE id =＆＃39;＆＃34;。$ id。＆＃34;＆＃39;＆＃34;;

Answer 3

您在更新查询中不需要VALUES('$name', '$fathers_name', '$gotra', '$image', '$village', '$company_name', '$address1', '$address2', '$city', '$pincod，'

缺少village=$village'

更改

$sql = "UPDATE members_data SET name='$name', fathers_name='$fathers_name', gotra='$gotra', image='$image', village=$village', company_name='$company_name', address1='$address1', address2='$address2', city='$city', pincode='$pincode', mobile1='$mobile1', mobile2='$mobile2', village_number='$village_number' )VALUES('$name', '$fathers_name', '$gotra', '$image', '$village', '$company_name', '$address1', '$address2', '$city', '$pincode', '$mobile1', '$mobile2', '$village_number' WHERE id= '".$id."'";

向

$sql = "UPDATE members_data SET name='$name', fathers_name='$fathers_name', gotra='$gotra', image='$image', village='$village', company_name='$company_name', address1='$address1', address2='$address2', city='$city', pincode='$pincode', mobile1='$mobile1', mobile2='$mobile2', village_number='$village_number' ) WHERE id= '$id' ";

用PHP更新数据库

3 个答案: