我想从data.frame
的每一行独立于其他行绘制随机样本。这是一个例子。此代码为每行选择相同的列,但我需要为每行选择独立的列。
library(plyr)
set.seed(12345)
df1 <- mdply(data.frame(mean=c(10, 15)), rnorm, n = 5, sd = 1)
df1
mean V1 V2 V3 V4 V5
1 10 10.58553 10.70947 9.890697 9.546503 10.60589
2 15 13.18204 15.63010 14.723816 14.715840 14.08068
> df1[ , -1]
V1 V2 V3 V4 V5
1 10.58553 10.70947 9.890697 9.546503 10.60589
2 13.18204 15.63010 14.723816 14.715840 14.08068
> sample(df1[, -1], replace = TRUE)
V3 V2 V5 V4 V4.1
1 9.890697 10.70947 10.60589 9.546503 9.546503
2 14.723816 15.63010 14.08068 14.715840 14.715840
> t(apply(df1[, -1], 1, sample))
[,1] [,2] [,3] [,4] [,5]
[1,] 10.70947 9.890697 10.60589 10.58553 9.546503
[2,] 14.71584 13.182044 14.08068 15.63010 14.723816
被修改
df1[ , -1]
V1 V2 V3 V4 V5
1 10.58553 10.70947 9.890697 9.546503 10.60589
2 13.18204 15.63010 14.723816 14.715840 14.08068
sample(df1[, -1], replace = TRUE)
V3 V2 V5 V4 V4.1
1 9.890697 10.70947 10.60589 9.546503 9.546503
2 14.723816 15.63010 14.08068 14.715840 14.715840
sample(df1[, -1], replace = TRUE)
为两行选择列V3
,V2
,V5
,V4
和V4
。但我要求它可以为V3
选择列V2
,V5
,V4
,V4
和first row
和/或任意组合second row
的五列。
答案 0 :(得分:3)
您可以将apply
与replace=TRUE
用于sample
t(apply(df1[,-1], 1, sample, replace=TRUE))
答案 1 :(得分:2)
您可以一次性对列索引进行采样,然后使用矩阵子集来避免使用apply
:
## Determine how many indices are required (nrow x (ncol - 1))
nsamp <- prod(dim(df1[, -1]))
## Sample from the number of desired columns, here 5 = ncol(df1[, -1])
mySamp <- sample.int(5, nsamp, replace = TRUE)
## Create a matrix of row and column indices
## Have to add 1 to mySamp to ignore first column of df1
myIdx <- cbind(rep(seq_len(nrow(df1)), ncol(df1) - 1), mySamp + 1)
## Return the corresponding values
matrix(df1[myIdx], nrow = nrow(df1))
# [,1] [,2] [,3] [,4] [,5]
# [1,] 9.890697 10.60589 9.546503 9.546503 10.70947
# [2,] 15.630099 14.71584 15.630099 14.723816 14.72382