Question

我有下一个json：

{
    "blabla": {
        "1": {
            "foo": "foo1",
            "bar": "bar1"
        },
        "22": {
            "foo": "foo22",
            "bar": "bar22"
        }
    }
}

是对象的int映射有没有办法将其转换为对象数组，如：

class FooBar
{
    public int id;
    public String foo;
    public String bar;
}

没有解析为map并迭代它以进行转换？

Answer 1

根据您粘贴的StaggeredGridLayoutManager，我可以假设类结构如下（...是的，您的json无法解析为您的json类。因为FooBar表示json为关键字，但id类包含FooBar作为成员变量。因此，它们无法相互转换。）：

id

而且，这是示例代码。

class FooBar {                                             
    public String foo;                                     
    public String bar;                                     
};                                                         

class FooBarObject {                                       
    public HashMap<String, FooBar> blabla;                 
    public void setBlabla(HashMap<String, FooBar> blabla) {
        this.blabla = blabla;                              
    }                                                      
    public HashMap<String, FooBar> getBlabla() {           
        return blabla;                                     
    }                                                      
};

但是，我猜错了......你真的想用import com.fasterxml.jackson.core.JsonProcessingException; import com.fasterxml.jackson.core.type.TypeReference; import com.fasterxml.jackson.databind.ObjectMapper; import java.util.HashMap; import java.util.Map; import java.util.Map.Entry; import java.util.Set; /** * Hello world! */ class FooBar { public String foo; public String bar; }; class FooBarObject { public HashMap<String, FooBar> blabla; public void setBlabla(HashMap<String, FooBar> blabla) { this.blabla = blabla; } public HashMap<String, FooBar> getBlabla() { return blabla; } }; public class App { static String target = "" + "{" + " \"blabla\": {" + " \"1\": {" + " \"foo\": \"foo1\"," + " \"bar\": \"bar1\"" + " }," + " \"22\": {" + " \"foo\": \"foo22\"," + " \"bar\": \"bar22\"" + " }" + " }" + "}"; public static void main(String[] args) throws Exception { FooBarObject blabla = new FooBarObject(); HashMap map = new HashMap<String, FooBar>(); map.put("1", new FooBar()); map.put("22", new FooBar()); blabla.setBlabla(map); ObjectMapper mapper = new ObjectMapper(); String json = mapper.writeValueAsString(blabla); System.out.println("--- BEGIN ---"); System.out.println(json); System.out.println("--- END ---"); blabla = mapper.readValue(target, FooBarObject.class); System.out.println("--- BEGIN ---"); for ( Map.Entry<String, FooBar> entry : blabla.blabla.entrySet() ) { String internal = mapper.writeValueAsString(entry.getValue()); System.out.println(entry.getKey() + ": " + internal); } System.out.println("--- END ---"); } }吗？

Array

如何使用jackson库将json map对象转换为对象数组

1 个答案: