如何检测Swift 2

时间:2015-07-26 23:22:05

标签: ios timeout touch appdelegate swift2

我正在尝试为我使用Swift 2开发的应用创建超时功能但是在swift 2中,您可以将此代码放在应用委托中并且它可以工作,但它不会检测到任何键盘印刷机,按钮印刷机,文本印刷机等:

override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {
    super.touchesBegan(touches, withEvent: event);
    let allTouches = event!.allTouches();

    if(allTouches?.count > 0) {
        let phase = (allTouches!.first as UITouch!).phase;
        if(phase == UITouchPhase.Began || phase == UITouchPhase.Ended) {
            //Stuff
            timeoutModel.actionPerformed();
        }
    }
}

在swift 2之前,我能够拥有AppDelegate子类UIApplication并覆盖sendEvent:像这样:

-(void)sendEvent:(UIEvent *)event
{
    [super sendEvent:event];

    // Only want to reset the timer on a Began touch or an Ended touch, to reduce the number of timer resets.
    NSSet *allTouches = [event allTouches];
    if ([allTouches count] > 0) {
        // allTouches count only ever seems to be 1, so anyObject works here.
        UITouchPhase phase = ((UITouch *)[allTouches anyObject]).phase;
        if (phase == UITouchPhaseBegan || phase == UITouchPhaseEnded)
            [[InactivityModel instance] actionPerformed];
    }
}

上面的代码适用于每次触摸,但只有在UIWindow的层次结构之上不存在视图时,swift等效项才有效吗?

有没有人知道如何检测应用程序中的每一次触摸?

3 个答案:

答案 0 :(得分:14)

由于我的应用程序中有类似内容,我只是尝试修复它:

  • sendEvent中覆盖UIWindow - 无效
  • 在委托中覆盖sendEvent - 不起作用

所以唯一的方法是提供自定义UIApplication子类。到目前为止,我的代码(适用于iOS 9)是:

@objc(MyApplication) class MyApplication: UIApplication {

  override func sendEvent(event: UIEvent) {
    //
    // Ignore .Motion and .RemoteControl event
    // simply everything else then .Touches
    //
    if event.type != .Touches {
      super.sendEvent(event)
      return
    }

    //
    // .Touches only
    //
    var restartTimer = true

    if let touches = event.allTouches() {
      //
      // At least one touch in progress?
      // Do not restart auto lock timer, just invalidate it
      //
      for touch in touches.enumerate() {
        if touch.element.phase != .Cancelled && touch.element.phase != .Ended {
          restartTimer = false
          break
        }
      }
    }

    if restartTimer {
      // Touches ended || cancelled, restart auto lock timer
      print("Restart auto lock timer")
    } else {
      // Touch in progress - !ended, !cancelled, just invalidate it
      print("Invalidate auto lock timer")
    }

    super.sendEvent(event)
  }

}

为什么有@objc(MyApplication)。那是因为Swift以与Objective-C不同的方式破坏了名称 - 它只是说 - 我在Objective-C中的类名是MyApplication

要使其正常工作,请打开您的info.plist并使用 Principal class 键添加行,MyApplicationMyApplication@objc(...)内的内容,而不是你的Swift类名)。原始密钥为NSPrincipalClass

enter image description here

答案 1 :(得分:0)

UIWindow还有一个sendEvent方法可以覆盖。这样您就可以跟踪自上次触摸屏幕以来的时间。斯威夫特4:

class IdlingWindow: UIWindow {
    /// Tracks the last time this window was interacted with
    var lastInteraction = Date.distantPast

    override func sendEvent(_ event: UIEvent) {
        super.sendEvent(event)
        lastInteraction = Date()
    }
}

如果您使用的是情节提要,则可以在didFinishLaunchingWithOptions

中加载
@UIApplicationMain
class AppDelegate: UIResponder, UIApplicationDelegate {
    var window: IdlingWindow?

    func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
        window = IdlingWindow(frame: UIScreen.main.bounds)
        window?.rootViewController = UIStoryboard.init(name: "Main", bundle: nil).instantiateInitialViewController()
        window?.makeKeyAndVisible()
        return true
    }
    :
}

extension UIApplication {
    /// Conveniently gets the last interaction time
    var lastInteraction: Date {
        return (keyWindow as? IdlingWindow)?.lastInteraction ?? .distantPast
    }
}

现在您应用中的其他地方,您可以检查是否存在不活动状态:

if UIApplication.shared.lastInteraction.timeIntervalSinceNow < -2 {
    // the window has been idle over 2 seconds
}

答案 2 :(得分:0)

@markiv答案就像一个咒语,有两个问题:

  1. keyWindow
    • “'keyWindow'在iOS 13.0中已过时:不应用于支持多个场景的应用程序,因为它会返回所有已连接场景的关键窗口”

可以这样解决:

let kw = UIApplication.shared.windows.filter {$0.isKeyWindow}.first 找到here

查看@matt的答案

  1. AppDelegate-我收到此消息:

    • 如果应用程序委托要使用主故事板文件,则必须实现window属性

一个可以继承UIWindow的子类-找到了答案here。将此与IdlingWindow类结合使用。

消息消失了。

var customWindow: IdlingWindow?    
var window: UIWindow? {
    get {
        customWindow = customWindow ?? IdlingWindow(frame: UIScreen.mainScreen().bounds)
        return customWindow
    }
    set { }
}