Question

我编写了以下代码，它接受数组的输入并将它拉伸。

例如

{18, 7, 9, 90}

应该返回：

{9, 9, 4, 3, 5, 4, 45, 45}

这是我写的代码：

import java.util.Arrays;

public class Stretching
{
  public static void main(String[] args)
  {
    int[] list = {18, 7, 9, 90};
    int[] list2 = stretch(list);

    System.out.println(Arrays.toString(list));
    System.out.println(Arrays.toString(list2));
  }
  public static int[] stretch(int[] array)
  {
    int[] stretched = new int[2*array.length];
    for (int i = 0; i < array.length; i++)
    {
      if (array[i]%2 == 1)
      {
        stretched[i] = array[i]/2;
        stretched[i] = array[i]/2 + 1;
      }
      else
      {
        stretched[i] = array[i]/2;
        stretched[i] = array[i]/2;
      }
    }
    return stretched;
  }
}

不幸的是，输出是这样的：

[9, 3, 4, 45, 0, 0, 0, 0]

如何解决此错误？

Answer 1

您正在重用引用原始数组中位置的i索引。相反，由于您正在扩展数组，因此目标索引应为：

if (array[i]%2 == 1)
{
    stretched[2 * i] = array[i]/2 + 1;
    stretched[2 * i + 1] = array[i]/2;
}
else
{
    stretched[2 * i] = array[i]/2;
    stretched[2 * i + 1] = array[i]/2;
}

Answer 2

此代码中存在一个非常大的错误。

  if (array[i]%2 == 1)
  {
    // Here array[i]/2+1 to index i
    stretched[i] = array[i]/2 + 1;
    // Here array[i]/2 to index i
    stretched[i] = array[i]/2;
  }
  else
  {
    // Here array[i]/2 to index i
    stretched[i] = array[i]/2;
    // Here array[i]/2 to index i
    stretched[i] = array[i]/2;
  }

在这里，您要在拉伸数组中为同一个索引分配两个值，您真正想要的是将它们分配给连续索引。

相反，您必须修改您的代码，如下所示

import java.util.Arrays;

class Stretching
{
  public static void main(String[] args)
  {
    int[] list = {18, 7, 9, 90};
    int[] list2 = stretch(list);

    System.out.println(Arrays.toString(list));
    System.out.println(Arrays.toString(list2));
  }
  public static int[] stretch(int[] array)
  {
    int[] stretched = new int[2*array.length];
    for (int i = 0; i < array.length; i++)
    {
      if (array[i]%2 == 1)
      {
        stretched[2 * i] = array[i]/2 + 1;
        stretched[2 * i + 1] = array[i]/2;
      }
      else
      {
        stretched[2 * i] = array[i]/2;
        stretched[2 * i + 1] = array[i]/2;
      }
    }
    return stretched;
  }
}

希望你能理解这个错误!!

数组输出被截断

2 个答案: