我想知道如何从处理程序提供文件。我正在使用go和gin而我已尝试过。
func DownloadHandler(c *gin.Context) {
c.File("./downloads/file.zip")
}
和
func DownloadConfigs(c *gin.Context) {
http.ServeFile(c.Writer, c.Request, "./downloads/file.zip")
}
这两种解决方案都没有点。
我对任何解决方案都持开放态度,因为杜松子酒与标准http lib兼容,我也可以使用非杜松子酒特定的解决方案
答案 0 :(得分:7)
以下是使用标准http包的完整工作示例。请注意,您使用的文件名或路径是相对于当前工作目录的。
func main() {
http.HandleFunc("/", func(w http.ResponseWriter, r *http.Request) {
http.ServeFile(w, r, "file")
})
err := http.ListenAndServe(":8080", nil)
if err != nil {
log.Fatal("ListenAndServe: ", err)
}
}
答案 1 :(得分:1)
更多使用直接使用c.FileAttachment 例如:-
func DownloadHandler(c *gin.Context) {
c.FileAttachment("./downloads/file.zip","filename.zip")
}
答案 2 :(得分:0)
只需使用gin.Context中的此函数: https://godoc.org/github.com/gin-gonic/gin#Context.File
这样的事情:
const DOWNLOADS_PATH = "downloads/"
ginRouter.GET("/download-user-file/:filename", func (ctx *gin.Context) {
fileName := ctx.Param("filename")
targetPath := filepath.Join(DOWNLOADS_PATH, fileName)
//This ckeck is for example, I not sure is it can prevent all possible filename attacks - will be much better if real filename will not come from user side. I not even tryed this code
if !strings.HasPrefix(filepath.Clean(targetPath), DOWNLOADS_PATH) {
ctx.String(403, "Look like you attacking me")
return
}
//Seems this headers needed for some browsers (for example without this headers Chrome will download files as txt)
ctx.Header("Content-Description", "File Transfer")
ctx.Header("Content-Transfer-Encoding", "binary")
ctx.Header("Content-Disposition", "attachment; filename="+fileName )
ctx.Header("Content-Type", "application/octet-stream")
ctx.File(targetPath)
})