Question

我为垒球队制作了一个小应用程序。我想建立以下关联：

模型Game有两列away_id，home_id，这两列都是Team.id的别名。

在Game模型中我有：

/**
 * belongsTo associations
 *
 * @var array
 */
    public $belongsTo = array(
        'Home' => array(
            'className' => 'Team',
            'foreignKey' => 'home_id', // also tried simply 'id'
            'conditions' => '',
            'fields' => '',
            'order' => ''
        ),
        'Away' => array(
            'className' => 'Team',
            'foreignKey' => 'away_id', // also tried simply 'id'
            'conditions' => '',
            'fields' => '',
            'order' => ''
        )
    );

在Team模型中我有：

public $virtualFields = ['home_id' => 'Team.id', 'away_id' => 'Team.id'];

和

/**
 * hasMany associations
 *
 * @var array
 */
    public $hasMany = array(
        'Game' => array(
                    'className' => 'Game',
                    'foreignKey' => 'home_id',
                    'dependent' => false,
                    'conditions' => '',
                    'fields' => '',
                    'order' => '',
                    'limit' => '',
                    'offset' => '',
                    'exclusive' => '',
                    'finderQuery' => '',
                    'counterQuery' => ''
                ),


// also tried only one 'Game' association with foreignKey => [home_id, away_id]
        'Game' => array(
                    'className' => 'Game',
                    'foreignKey' => 'away_id',
                    'dependent' => false,
                    'conditions' => '',
                    'fields' => '',
                    'order' => '',
                    'limit' => '',
                    'offset' => '',
                    'exclusive' => '',
                    'finderQuery' => '',
                    'counterQuery' => ''
                )
    );

收到以下错误：

注意：＆＃34; Psychouts＆＃34;是下面SQL中唯一不可解释的外观;它是数据库名称（以及我的团队名称，henh）。

Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'Team.id' in 'field list'

SQL查询：SELECT Game。id，Game。when，Game。cancelled，Game。{ {1}}，field。Game，home_id。Game，away_id。Game，score_us。{{1 }，Game。score_them，Home。id，Home。captain_id，Home。name ，Home。wins，Home。losses，Home。ties，Home。scored，（ Home。allowed）AS Team，（id。Home__home_id）AS Team，id。Home__away_id ，Away。id，Away。captain_id，Away。name，Away。wins，{ {1}}。Away，losses。Away，ties。Away，（scored。Away）AS { {1}}，（allowed。Team）AS id FROM Away__home_id。Team AS id LEFT JOIN Away__away_id。 psychouts AS games ON（Game。psychouts = teams。Home）LEFT JOIN Game。home_id AS Home ON（id。psychouts = teams。Away）WHERE 1 = 1 LIMIT 20

Answer 1

根据AD7six的评论，经过测试，似乎正确的解决方案是：

在Team模型中，删除我建议的虚拟字段，然后按如下方式定义Game关联：

/**
 * belongsTo associations
 *
 * @var array
 */
    public $belongsTo = array(
        'Game' => array(
            'className' => 'Game',
            'foreignKey' => ['OR' => ['Game.home_id = Team.id', 'Game.away_id = Team.id']]
            'conditions' => '',
            'fields' => '',
            'order' => ''
        ),
    );

在Game模型中，像往常一样定义Team关联：

/**
 * belongsTo associations
 *
 * @var array
 */
    public $belongsTo = array(
        'Team' => array(
            'className' => 'Team',
            'foreignKey' => 'id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        ),
    );

多个hasMany通过列别名

1 个答案: