Question

每当我输入一个10位数字时，我在getnum函数中从数据库中获取一个随机值，但是当我输入一个小于10位的数字时，eveything工作正常。
请告诉我们如何在getnum函数中传递一个10位数字。

  public void callme(View v)
{
    Intent i= new Intent();
    i.setData(Uri.parse("tel:" + mydb.getnum(id_To_Update)));
    i.setAction(Intent.ACTION_CALL);
    startActivity(i);
}

这是我在MyDBHandler中的getnum函数

 public Integer getnum(int id){
   int dat =0;
    SQLiteDatabase db = getReadableDatabase();
    Cursor cursor = db.rawQuery(
            "SELECT number FROM userdata1 where id="+id+"", null);
    if(cursor.moveToFirst()) {
        dat = cursor.getInt(0);
    }

    return dat;
}

这就是我创建MyDBHandler的方式

public class MyDBHandler extends SQLiteOpenHelper {

public static final int DATABASE_VERSION=1;
public static final String DATABASE_NAME = "ome1.db";
public static final String TABLE_NAME = "userdata1";

public static final String COLUMN_ID = "id";
public static final String COLUMN_NAME = "name";
public static final String COLUMN_EMAIL = "email";
public static final String COLUMN_AMOUNT = "amount";
public static final String COLUMN_NUMBER = "number";

public MyDBHandler(Context context)

{
    super(context, DATABASE_NAME , null, 1);

}

@Override
public void onCreate(SQLiteDatabase db) {

        db.execSQL(
                "create table userdata1 " +
                        "(id integer primary key, name text,email text,amount integer,number integer)"
        );


}

Answer 1

在上面的代码中将int更改为long，即

public Long getnum(int id){
    Long dat=null;
    SQLiteDatabase db = getReadableDatabase();

    Cursor cursor = db.rawQuery(
            "SELECT number FROM userdata1 where id="+id+"", null);
    if(cursor.moveToFirst()) {
        dat = cursor.getLong(0);
    }

将数据从数据库传递到intent

1 个答案: