我想通过调用多播委托来组合两个函数调用返回的结果。但我一直得到一个例外,说del是一个变量但是像方法一样使用。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace MultiDelegateConsoleApplication
{
public delegate void SampleMultiDelegate(string args,out string SampleString);
class Program
{
public static void SayHello(string args,out string s1)
{
s1 = "Hello " + args;
}
public static void SayGoodbye(string args,out string s2)
{
s2 = "Goodbye " + args;
}
static void Main(string[] args)
{
SampleMultiDelegate sampleMultiDelegate = new SampleMultiDelegate(SayHello);
sampleMultiDelegate += SayGoodbye;
string param1 = "Chiranjib";
string param2,param3;
Console.WriteLine("**************Individual Function Invoke***********");
SayHello(param1,out param2);
SayGoodbye(param1, out param3);
Console.WriteLine("**************Multicast Delegate Invoke***********");
sampleMultiDelegate(param1,out param2);
Console.WriteLine(param2); //The multicast delegate will always return the result of the last function
string result;
foreach (Delegate del in sampleMultiDelegate.GetInvocationList())
{
result = del(param1,out param2);
}
Console.ReadKey();
Console.ReadLine();
}
}
}
请您解释并帮我解决错误?
答案 0 :(得分:2)
您需要将调用列表中的每个函数强制转换为委托类型,以便能够使用普通函数调用语法:
void Main()
{
var sampleMultiDelegate = new SampleMultiDelegate(SayHello);
sampleMultiDelegate += SayGoodbye;
var param1 = "Chiranjib";
string param2;
string result = "";
foreach (var del in sampleMultiDelegate.GetInvocationList())
{
var f = (SampleMultiDelegate)del;
f(param1, out param2);
result += param2 + "\r\n";
}
Console.WriteLine(result);
}
还修复了以下事实:当您的委托调用返回void
时,无法获得任何结果。
答案 1 :(得分:1)
此代码可用于获取每个结果。关键是我的unfurl
函数,它改变了返回类型。
SampleMultiDelegate sampleMultiDelegate = new SampleMultiDelegate(SayHello);
sampleMultiDelegate += SayGoodbye;
string param1 = "Chiranjib";
Func<SampleMultiDelegate, string, string> unfurl =
(d, p1) =>
{
string r;
d(p1, out r);
return r;
};
string result =
String.Join(
Environment.NewLine,
sampleMultiDelegate
.GetInvocationList()
.Cast<SampleMultiDelegate>()
.Select(d => unfurl(d, param1)));
Console.WriteLine(result);