好的，我知道这纯粹是学术性的，因为1: some string命令可以达到我的期望。
我有一个文本文件，其中我想要编号的字符串（行）。我想知道是否可以编写一个模拟它的批处理，并让我可以灵活地将标记整数移动到字符串中的任何位置。
例如，标准输出为1)some string
让我们说我想要
somestring........(1) （不使用Windows资源管理器中的查找和替换）或s 1] somestring或$(document).ready(function(){
$("#jquery_jplayer_1").jPlayer({
ready: function () {
$(this).jPlayer("setMedia", {
title: MediaTitle,
mp3: MediaURL
});
},
remainingDuration: true,
defaultPlaybackRate: 1, /* <-- I'd like to change the playback rate
when I click a button */
toggleDuration: true
});
});
答案 0 :(得分：1)
编辑：我修改了代码，以便在该行的任何位置插入行号：
@echo off
setlocal DisableDelayedExpansion
rem Define the format of output lines; for example
rem To show "(lineNo) line" use:
set "format=(!lineNo!) !line!"
rem To show "20 chars of line (lineNo) rest of line" use:
set "format=!line:~0,20! (!lineNo!) !line:~20!"
rem and adjust each line read appending 20 spaces
rem To show "line (lineNo placed at column 75)" use:
set "format=!line:~0,73! (!lineNo!)"
rem and adjust each line read appending 73 spaces
rem To show line numbers with left zeros, start lineNo with the proper
rem number of zeros and modify the format accordingly; for example:
set lineNo=100
set "format=!line:~0,73! (!lineNo:~1!)"
setlocal EnableDelayedExpansion
copy %1 "%~1.tmp" > NUL
set "EOF=%random%%random%%random%"
echo :%EOF%EOF:>> "%~1.tmp"
REM set lineNo=0
call :ReadLines < "%~1.tmp"
del "%~1.tmp"
goto :EOF
:ReadLines
set "line="
set /P "line="
if "!line!" equ ":%EOF%EOF:" goto :EOF
set "line=!line! "
set /A lineNo+=1
echo %format%
goto ReadLines
输出示例：
@echo off (01)
setlocal DisableDelayedExpansion (02)
(03)
rem Define the format of output lines; for example (04)
(05)
rem To show "(lineNo) line" use: (06)
set "format=(!lineNo!) !line!" (07)
(08)
rem To show "20 chars of line (lineNo) rest of line" use: (09)
set "format=!line:~0,20! (!lineNo!) !line:~20!" (10)
rem and adjust each line read appending 20 spaces (11)
(12)
rem To show "line (lineNo placed at column 75)" use: (13)
set "format=!line:~0,73! (!lineNo!)" (14)
rem and adjust each line read appending 73 spaces (15)
(16)
rem To show line numbers with left zeros, start lineNo with the proper (17)
rem number of zeros and modify the format accordingly; for example: (18)
set lineNo=100 (19)
set "format=!line:~0,73! (!lineNo:~1!)" (20)
(21)
(22)
setlocal EnableDelayedExpansion (23)
copy %1 "%~1.tmp" > NUL (24)
set "EOF=%random%%random%%random%" (25)
echo :%EOF%EOF:>> "%~1.tmp" (26)
REM set lineNo=0 (27)
call :ReadLines < "%~1.tmp" (28)
del "%~1.tmp" (29)
goto :EOF (30)
(31)
:ReadLines (32)
set "line=" (33)
set /P "line=" (34)
if "!line!" equ ":%EOF%EOF:" goto :EOF (35)
set "line=!line! (36)
set /A lineNo+=1 (37)
echo %format% (38)
goto ReadLines (39)
答案 1 :(得分：0)
@echo off
SET SNO=1
FOR /f "tokens=*" %%X IN (friends.txt) DO (call :subroutine %%X)
GOTO :eof
:subroutine
:: This is the interesting part where the value of the SNO can be
:: moved around.If you want the SNO bang in the middle then
:: then that that's another project ! Moreover moving it to the end
:: is problematic if the strings don't have the same number
:: of characters. The result is not visually pleasant in that case
echo.
echo (%SNO%) %1>>numbered.txt
set /a SNO+=1
GOTO :eof