Question

我在UITableView中构建ViewDidLoad，如下所示：

- (void)viewDidLoad
{
    CGSize viewSize = self.view.frame.size;
mainScroll = [[UIScrollView alloc] initWithFrame:CGRectMake(0, 35, viewSize.width, viewSize.height -149)];
[mainScroll setPagingEnabled:YES];
[mainScroll setShowsHorizontalScrollIndicator:NO];
[mainScroll setDelegate:self];
[mainScroll setTag:101010];

    // #1
    UIScrollView *scroll1 = [[UIScrollView alloc] initWithFrame:CGRectMake(0, 0, viewSize.width, viewSize.height -149)];
    UITableView *table101 = [[UITableView alloc] initWithFrame:CGRectMake(0, 0, viewSize.width, viewSize.height -149) style:UITableViewStylePlain];
    [table101 setDataSource:self];
    [table101 setDelegate:self];
    [table101 setBackgroundColor:[UIColor clearColor]];
    [table101 setTag:101];
    [table101 setSeparatorStyle:UITableViewCellSeparatorStyleNone];

    [scroll1 addSubview:table101];

    // #2
    UIScrollView *scroll2 = [[UIScrollView alloc] initWithFrame:CGRectMake(viewSize.width, 0, viewSize.width, viewSize.height -149)];
    UITableView *table102 = [[UITableView alloc] initWithFrame:CGRectMake(0, 0, viewSize.width, viewSize.height -149) style:UITableViewStylePlain];
    [table102 setDataSource:self];
    [table102 setDelegate:self];
    [table102 setBackgroundColor:[UIColor clearColor]];
    [table102 setTag:102];
    [table102 setSeparatorStyle:UITableViewCellSeparatorStyleNone];

    [scroll2 addSubview:table102];

[mainScroll addSubview:scroll1];
[mainScroll addSubview:scroll2];
[mainScroll setContentSize:CGSizeMake(viewSize.width *2, viewSize.height -149)];



}

在TableViewCell我用过这个：

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *cellIdentifier = @"Cell";
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:cellIdentifier];

    if (cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:cellIdentifier];
        [cell setSeparatorInset:UIEdgeInsetsMake(0, 15, 0, 15)];

    }

    NSMutableArray *mutableArray;

    if (tableView.tag == 101) {
        mutableArray = self.itemsInTable_Molhaq;

    } else if (tableView.tag == 102) {
        mutableArray = self.itemsInTable_Ziyarah;
    }

    NSString *labelString = [[mutableArray objectAtIndex:indexPath.row] objectForKey:@"Title"];
    NSInteger indentLevel = [[[mutableArray objectAtIndex:indexPath.row] objectForKey:@"Level"] intValue];

    [cell.textLabel setAttributedText:[self attributeString:labelString indentLevel:indentLevel]];

return cell;

}

一切正常，但Xcode告诉我这个：

Unsupported configuration prototype table cells must have reuse identifiers

我错过了什么？我可以得到一些帮助吗？

Answer 1

-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath (NSIndexPath*)indexPath 
{
static NSString *cellIdentifier = @"wot";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:cellIdentifier forIndexPath:indexPath];

if (!cell)
    cell = [[UITableViewCell alloc] initWithStyle: someStyle reuseIdentifier: cellIdentifier];

return cell;
}

可能有帮助。

Answer 2

很清楚错误说的是什么。您已在故事板中创建了原型单元格，但没有为其指定标识符。转到故事板并查看单元格的属性。填写标识符。

不支持的配置原型表单元必须具有重用标识符

2 个答案: