我在DataGridTemplateColumn中有一个ListView,如果鼠标光标位于ListView中的一个项目上并且用户试图滚动DataGrid,则DataGrid不会滚动。
我尝试了以下但仍然会发生:
<ListView ScrollViewer.CanContentScroll="False" ScrollViewer.HorizontalScrollBarVisibility="Disabled" ScrollViewer.VerticalScrollBarVisibility="Disabled" ...
编辑:在下面提供使用它的示例,我使用ListView使项目溢出。
<DataGridTemplateColumn Header="Name" Width="120" ScrollViewer.IsDeferredScrollingEnabled="True">
<DataGridTemplateColumn.CellTemplate>
<DataTemplate>
<ListView ScrollViewer.CanContentScroll="False" ScrollViewer.HorizontalScrollBarVisibility="Disabled" ScrollViewer.VerticalScrollBarVisibility="Disabled" VerticalAlignment="Center" ItemsSource="{Binding DataList}">
<ListView.ItemsPanel>
<ItemsPanelTemplate>
<WrapPanel Width="{Binding (FrameworkElement.ActualWidth), RelativeSource={RelativeSource AncestorType=ScrollContentPresenter}}" ItemWidth="{Binding (ListView.View).ItemWidth, RelativeSource={RelativeSource AncestorType=ListView}}" ItemHeight="{Binding (ListView.View).ItemHeight, RelativeSource={RelativeSource AncestorType=ListView}}"/>
</ItemsPanelTemplate>
</ListView.ItemsPanel>
<ListView.ItemTemplate>
<DataTemplate>
<TextBlock>
<Hyperlink TextDecorations="{x:Null}" NavigateUri="{Binding Path=.}" RequestNavigate="Name_RequestNavigate">
<TextBlock Padding="1" Text="{Binding Path=., Converter={StaticResource NameToLocale}}"/>
</Hyperlink>
</TextBlock>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
</DataTemplate>
</DataGridTemplateColumn.CellTemplate>
</DataGridTemplateColumn>
答案 0 :(得分:3)
尝试这种方式:
A)更改列表视图ControlTemplate
以从中移除ScrollViewer
:
<ListView>
<ListView.Template>
<ControlTemplate>
<ItemsPresenter/>
</ControlTemplate>
</ListView.Template>
...
</ListView>
B)另一种方法是在this answer上为父元素创建行为
// Used on sub-controls of an expander to bubble the mouse wheel scroll event up
public sealed class BubbleScrollEvent : Behavior<UIElement>
{
protected override void OnAttached()
{
base.OnAttached();
AssociatedObject.PreviewMouseWheel += AssociatedObject_PreviewMouseWheel;
}
protected override void OnDetaching()
{
AssociatedObject.PreviewMouseWheel -= AssociatedObject_PreviewMouseWheel;
base.OnDetaching();
}
void AssociatedObject_PreviewMouseWheel(object sender, MouseWheelEventArgs e)
{
e.Handled = true;
var e2 = new MouseWheelEventArgs(e.MouseDevice, e.Timestamp, e.Delta);
e2.RoutedEvent = UIElement.MouseWheelEvent;
AssociatedObject.RaiseEvent(e2);
}
}
<SomePanel>
<i:Interaction.Behaviors>
<viewsCommon:BubbleScrollEvent />
</i:Interaction.Behaviors>
</SomePanel>