Question

我想在c ++中创建一个有三个选项的程序。

用户将在控制台中写入文本，此文本将使用某种经过修改的xor密码加密，加密文本将保存为文本文件。
将导入预先存在的文本文件，以相同方式加密，加密文本将像以前一样保存为文本文件。
将导入加密的文本文件并将其解密，结果将另存为文本文件。

每次用户输入文本文件的目的地和名称，即C:\Users\john\Desktop\（需要反斜杠） xor密码的密钥也只是两个字符，即a，b。我写了一个算法，案例2没有正常工作（或很少工作）。例如，如果我有文件＆＃34;你好我的名字是约翰！＆＃34;或者简单的东西，它将被正确地加密和解密，但如果我从互联网上复制粘贴一些文章，那就有问题，它不起作用。它仅解密原始文本的某些行，其余的是随机字符/符号...它必须是换行符的内容？我不知道出了什么问题。

代码是：

#include <iostream>
#include <string>
#include <fstream>

using namespace std;

int main()
{
    int option,choice;
    char temp1,temp2;
    do {
    cout << "Press:\n1.To create text, encrypt it and save it as a text        file\n2.To import text file and encrypt it\n3.To import text file and decrypt it\n\n\n";
    cin >> choice;
    if (choice==1)  {
        string text,coded,directory1,filename1;
        cout << "Enter the text to be encrypted:\n\n\n";
        fflush(stdin);
        getline(cin,text);
        cout << "Enter the two keys for the encryption (two characters):\n";
        cin >> temp1 >> temp2;
        for (int i=0;i<text.size();i++)   {
                coded+=text[i] ^ ((int(temp1)+i)%temp2);
        }
        cout << "The encrypted text message is:\n\n\n" << coded << "\n";
        cout << "Enter the path where the encrypted text will be saved (with \\ at the end):\n";
        fflush(stdin);
        getline(cin,directory1);
        cout << "Enter the name of the text file:\n";
        getline(cin,filename1);
        ofstream data((directory1 + filename1 + ".txt").c_str());
        data << coded << "\n";
        data.close();
    }
    else if (choice==2) {
        string directory1,directory2,filename1,filename2;
        cout << "Enter the path where the file to be encrypted will be imported from:\n";
        fflush(stdin);
        getline(cin,directory1);
        cout << "Enter the name of the text file:\n";
        getline(cin,filename1);
        ifstream data_input((directory1 + filename1 + ".txt").c_str());
        cout << "Enter the two keys for the encryption (two characters):\n";
        cin >> temp1 >> temp2;
        cout << "Enter the path where the encrypted text will be saved (with \\ at the end):\n";
        fflush(stdin);
        getline(cin,directory2);
        cout << "Enter the name of the text file:\n";
        getline(cin,filename2);
        ofstream data_output((directory2 + filename2 + ".txt").c_str());
        cout << "The encrypted text message is:\n\n\n";
        while (!data_input.eof())   {
            string text,coded;
            fflush(stdin);
            getline(data_input,text);
            for (int i=0;i<text.size();i++)   {
                    coded+=text[i] ^ ((int(temp1)+i)%temp2);
            }
            cout << coded << endl;
            data_output << coded << endl;
        }
        data_input.close();
        data_output.close();
    }
    else if (choice==3) {
        string directory1,directory2,filename1,filename2;
        cout << "Enter the path where the encrypted text file will be imported from:\n";
        fflush(stdin);
        getline(cin,directory1);
        cout << "Enter the name of the text file:\n";
        getline(cin,filename1);
        ifstream data_input((directory1 + filename1 + ".txt").c_str());
        cout << "Enter the two keys for the encryption (two characters):\n";
        cin >> temp1 >> temp2;
        cout << "Enter the path where the encrypted text will be saved (with \\ at the end):\n";
        fflush(stdin);
        getline(cin,directory2);
        cout << "Enter the name of the text file:\n";
        getline(cin,filename2);
        ofstream data_output((directory2 + filename2 + ".txt").c_str());
        cout << "The decrypted text message is:\n\n\n";
        while (!data_input.eof())   {
            string coded,decoded;
            fflush(stdin);
            getline(data_input,coded);
            for (int i=0;i<coded.size();i++)   {
                decoded+=coded[i] ^ ((int(temp1)+i)%temp2);
            }
            cout << decoded << endl;;
            data_output << decoded << endl;;
        }
        data_input.close();
        data_output.close();
    }
    cout << "\n\n\nEnter 0 to exit or 1 to return to the main menu..:\n";
    cin >> option;
    } while (option);
    cin.get();
}

哦，我没有很多c ++的经验，我去年刚开始，所以不要对我很难！

加密和解密文本文件

0 个答案: